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sleet_krkn [62]
3 years ago
13

50 POINTS BRAINLIEST MATH

Mathematics
2 answers:
MrRa [10]3 years ago
6 0

Answer:

B=\frac{2A}{h}-b

Step-by-step explanation:

To solve this B needs to be isolated. First we must multiply both sides of the equation by 2 to get rid of the fraction on the left side. Next, divide both sides by h to get rid of the h on the left side. Finally, subtract b form both sides to get B by itself.

Eddi Din [679]3 years ago
6 0
Your answer would be b=2a/h-B
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I will mark brainliest!
Harrizon [31]

Answer:

a + 56.75 = 76.75

Step-by-step explanation:

that is because ,money raised on first day(a) + money raised on second day = 76.75

that gives us,  a = $20

3 0
3 years ago
Read 2 more answers
Draw a line through each point using the given slope. What do you notice about the two lines?
morpeh [17]
I think the answer is that they are parallel
5 0
3 years ago
B) T is due north of C, calculate the bearing of B from C
choli [55]

Answer:

(a) 52°

(b) 322°

Step-by-step explanation:

(a) The details of the circle are;

The diameter of the circle = AOC

The center of the circle = Point O

The point the line AT cuts the circle = Point B

The point the tangent PT touches the circle = Point C

Angle ∠COB = 76°

We have that angle AOB and angle COB are supplementary angles, therefore;

∠AOB + ∠COB = 180°

∠AOB = 180° - ∠COB

∴ ∠AOB = 180° - 76° = 104°

∠AOB = 104°

OA = OB = The radius of the circle

Therefore, ΔAOB  =  An isosceles triangle

∠OAB = ∠OBA by base angles of an isosceles triangle are equal

∠AOB + ∠OAB + ∠OBA = 180° by angle summation property

∴ ∠AOB + ∠OAB + ∠OBA = ∠AOB + ∠OAB + ∠OAB = ∠AOB + 2×∠OAB = 180°

∠OAB = (180° - ∠AOB)/2

∴ ∠OAB = (180° - 104°)/2 = 38°

∠TAC = ∠OAB = 38° by reflexive property

AOC is perpendicular to tangent PT at point C, by tangent to a circle property, therefore;

∠TCA = 90° and ΔTCA = A right triangle

∠TAC + ∠ATC + ∠TCA = 180° by angle sum property

∠ATC = 180° - (∠TAC + ∠TCA)

∴ ∠ATC = 180° - (38° + 90°) = 52°

Angle ATC = 52°

(b) In ΔABC, ∠ABC = Angle subtended by the diameter = 90°

∴ ΔABC = A right triangle

∠ABC and ∠TBC are supplementary angles, therefore;

∠ABC + ∠TBC = 180°

∠TBC = 180° - ∠ABC

∴ ∠TBC = 180° - 90° = 90°

∠TCB = 180° - (∠TBC + ∠ATC)

∴ ∠TCB = 180° - (90° + 52°) = 38°

The bearing of B from C = (360° - 38°) = 322°.

7 0
2 years ago
How are unit rates, constant of proportionality, and scale factors are related.
vfiekz [6]
I found this online I hope it helps a little if not, then sorry.
6 0
2 years ago
Kim owes her friend $245 and plans to pay $35 per week. write an equation for the function that shows the amount Kim owes after
nevsk [136]

35x=245

so you would divide both sides by 35

x=7

so it would take her 7 weeks or 1 month and 3 weeks to pay her friend back

Brainliest please

7 0
3 years ago
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