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bezimeni [28]
3 years ago
9

When an ionic compound dissolves in water: When an ionic compound dissolves in water: the solvent-solute attractive forces overc

ome the solute-solute attractions. the positive end of water dipoles attract the negative ions. the negative end of water dipoles attract the positive ions. each of the above (A, B, and C) occurs. none of the above (A, B, or C) occurs.
Chemistry
1 answer:
oksano4ka [1.4K]3 years ago
8 0

Answer:

each of the above (A, B, and C) occurs

Explanation:

When an ionic compound dissolves in the water, the following happens :

-- the solvent solute attractive forces tries to overcome the solute solute attractions.

-- the water dipoles' negative end attracts the positive ions

--  the water dipoles' positive end attracts the negative ions

For example,

NaCl which is an ionic compound and also a strong electrolyte, it dissociates into water on the hydrated Na cations as well as Cl anions.

In water, the oxygen has negative charge and thus attracts the positive ions of the sodium, whereas the hydrogen is of positive and it attract the ions of chlorine which is negative.

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Note that
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How a cation is formed by an atom?​
fenix001 [56]

Answer:

Cations are positively charged atoms and hence we need to make the atom positively charged in order to get a cation

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4 0
3 years ago
Given that a for HBrO is 2. 8×10^−9 at 25°C. What is the value of b for BrO− at 25°C?
lara [203]

If Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

<h3>What is base dissociation constant? </h3>

The base dissociation constant (Kb) is defined as the measurement of the ions which base can dissociate or dissolve in the aqueous solution. The greater the value of base dissociation constant greater will be its basicity an strength.

The dissociation reaction of hydrogen cyanide can be given as

HCN --- (H+) + (CN-)

Given,

The value of Ka for HCN is 2.8× 10^(-9)

The correlation between base dissociation constant and acid dissociation constant is

Kw = Ka × Kb

Kw = 10^(-14)

Substituting values of Ka and Kw,

Kb = 10^(-14) /{2.8×10^(-9) }

= 3.5× 10^(-6)

Thus, we find that if Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

DISCLAIMER: The above question have mistake. The correct question is given as

Question:

Given that Ka for HBrO is 2. 8×10^−9 at 25°C. What is the value of Kb for BrO− at 25°C?

learn more about base dissociation constant:

brainly.com/question/9234362

#SPJ4

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2 years ago
What element has greatest atomic radius from group 3?
stira [4]

Answer:

i think iron

Explanation:

i not sure with my ans

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