Someone please help asap

A grocery cart with a mass of 15 kg is pushed at constant speed along an aisle by a force fp = 12 n which acts at an angle of 17

Korolek [52]

Given:

Mass of cart: 15kg

Aisle length = 14m

Angle = 17° below the horizontal

Force fp = 12 N

So, the solution would be like this for this specific problem:

1) W(by applied force) = F(applied) x s x cosθ 
=>W(a) = 12 x 14 x cos17* = 160.66 J 

2) By F(net) = F(applied) - F(friction) 
=>As v = constant => a = 0 => F(net) = 0
=>F(applied) = F(friction)
=>W(friction) = -F(friction) x s
=>W(friction) = -F(applied) x s
=>W(f) = -12 x 14 x cos17* = -160.56 J 

3) 0, as the displacement is perpendicular to Force 

4) 0, as the displacement is perpendicular to Force

To add, the force that is applied to an object by a person or another object is called the applied force.

8 0

3 years ago

The time T in seconds for a pendulum of length L feet to make one swing is given by Upper T=2\pi \sqrt((L)/(36)). How long is a

Andreyy89

Answer:

3.6ft

Explanation:

Using= 2*π*sqrt(L/32)

To solve for L, first move 2*n over:

T/(2*π) = sqrt(L/32)

Next,eliminate the square root by squaring both sides

(T/(2*π))2 = L/32

or

T2/(4π2) = L/32

Lastly, multiply both sides by 32 to yield:

32T2/(4π2) = L

and simplify:

8T²/π²= L

Hence, L(T) = 8T²/π²

But T = 2.1

Pi= 3.14

8(2.1)²/3.14²

35.28/9.85

= 3.6feet

5 0

3 years ago

a block of wood loses 160 j of gravitational potential energy as it slides down a ramp. if it has 90 J of kinetic energy at the

Nataly_w [17]

It would go slower there needs to be more gravity to go faster

3 0

4 years ago

Read 2 more answers

A 0.140-kg baseball is pitched horizontally at 33.6 m/s. When a player hits the ball, it moves at the

Mars2501 [29]

Answer:

F = 1176 N

Explanation:

Given that,

Mass of a baseball, m = 0.140-kg

Initial speed of the baseball, u = 33.6 m/s

Final speed of the baseball, v = -33.6 m/s (in opposite direction)

The time of contact of the bat and the ball, t = 0.008 s

We need to find the average force the bat exerts on the ball. The force acting on the ball is given by :

$F=ma\\\\F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.14(-33.6-33.6)}{0.008}\\F= -1176\ N$

So, the average force the bat exerts on the ball is 1176 N.

7 0

3 years ago

Two electric charges, held a distance, dd, apart experience an electric force of magnitude, FF, between them. If one of the char

lorasvet [3.4K]

Answer:

$F'=2F$

Explanation:

The Coulomb's law states that the magnitude of the electrostatic force between two charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them:

$F=\frac{kq_1q_2}{d^2}$

In this case, we have $q_1'=2q_1$ :

$F'=\frac{kq'_1q_2}{d^2}\\F'=\frac{k(2q_1)q_2}{d^2}\\F'=2\frac{kq_1q_2}{d^2}\\F'=2F$

3 0

3 years ago