Answer:
1.08 m/s
Explanation:
This can be solved with two steps, first we need to find the time taken to fall 9.5 m, then we can divide the horizontal distance covered with time taken to calculate the velocity.
Time taken to fall 9.5 m
vertical acceleration = a = 9.8 m/s^2.
vertical velocity = 0, (since there is only horizontal component for velocity,
)
distance traveled s = 9.5 m.
Substituting these values in the equation
⇒ t= 1.392 sec
Velocity needed
We know the time taken (1.392 s) to travel 1.5 m,
So velocity = 1.5 m / 1.392 s = 1.08 m/s
hence velocity of the diver must be at least 1.08 m/s
Answer:
400000
Explanation:
So first solve one part:
(3.25 * 10^5)
(3.25 * 100,000)
= 325000
Then solve the next part:
(7.5 * 10^4)
(7.5 * 10000)
= 75000
Now lastly, add the two answers:
325000 + 75000 = 400000
Therefore,
(3.25 x 10^5) + (7.5 x 10^4) = 400000
I believe it is “runs on parallel circuits”! my bad if incorrect
<u>Answer:</u> The steel wire will stretch up to 1837.5 mm
<u>Explanation:</u>
We are given:
Mass = 25 kg
Length of wire = 10 m
Area of cross-section of wire = 
(Conversion factor: 
)
To calculate the change in stretching, we use the equation:
where,
E = young modulus of steel = 
F = force exerted by the weight = m g = 
l = length of wire = 10 m
A = area of cross section = 
= change in length = ?
Putting values in above equation, we get:
Converting above value in mili meters, we use the conversion factor:
1 m = 1000 mm
So, 1.8375 m = 1837.5 mm
Hence, the steel wire will stretch up to 1837.5 mm
