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Nadya [2.5K]
3 years ago
13

Use your understanding of heat loss to ESTIMATE the cost of the lost energy through one standard window during an average summer

day in Maryland. Use $0.17 per kWh as your energy cost.
Physics
1 answer:
miskamm [114]3 years ago
3 0

Answer:

The cost of energy is $ 0.34.

Explanation:

The energy is the capacity to do work.

The energy is a scalar quantity and its SI unit is Joule.

The commercial unit of energy is kWh.

Cost of 1 kWh energy = $ 0.17

energy loss by standard window is 2 kWh .

So, the cost of lost of energy is

Cost = $ 0.17 x 2 = $ 0.34

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What must the diver's minimum speed be just as she leaves the top of the cliff so that she will miss the ledge at the bottom, wh
Dafna1 [17]

Answer:

1.08 m/s

Explanation:

This can be solved with two steps, first we need to find the time taken to fall 9.5 m, then we can divide the horizontal distance covered with time taken to calculate the velocity.

Time taken to fall 9.5 m

vertical acceleration = a = 9.8 m/s^2.

vertical velocity = 0, (since there is only horizontal component for velocity, )

distance traveled  s = 9.5 m.

Substituting these values in the equation

s= u \timest+0.5at^{2}

t= \sqrt{\frac{2s}{g} }

t=\sqrt{\frac{2\times9.5}{9.8} }

⇒ t= 1.392 sec

Velocity needed

We know the time taken (1.392 s) to travel 1.5 m,

So velocity = 1.5 m / 1.392 s = 1.08 m/s

hence velocity of the diver must be at least 1.08 m/s

4 0
3 years ago
What is (3.25 x 10^5) + (7.5 x 10^4)?
ivanzaharov [21]

Answer:

400000

Explanation:

So first solve one part:

(3.25 * 10^5)

(3.25 * 100,000)

= 325000

Then solve the next part:

(7.5 * 10^4)

(7.5 * 10000)

= 75000

Now lastly, add the two answers:

325000 + 75000 = 400000

Therefore,

(3.25 x 10^5) + (7.5 x 10^4) = 400000

5 0
2 years ago
Read 2 more answers
Can someone help me in this one :)
djyliett [7]
I believe it is “runs on parallel circuits”! my bad if incorrect
3 0
3 years ago
which of the following is not necessary in a great summary?your investigayltion, your predicatio, excuses, possible errors?
zloy xaker [14]

Excuse are not acceptable


5 0
3 years ago
A steel wire has a cross sectional area of 1.5 x 10^-4 cm^2 and a length of 10.0 m. By how much will it stretch if a 25 kg weigh
larisa86 [58]

<u>Answer:</u> The steel wire will stretch up to 1837.5 mm

<u>Explanation:</u>

We are given:

Mass = 25 kg

Length of wire = 10 m

Area of cross-section of wire = 1.5\times 10^{-4}cm^2=1.5\times 10^{-8}m^2    (Conversion factor:  1cm^2=10^{-4}m^2 )

To calculate the change in stretching, we use the equation:

E=\frac{Fl}{A\Delta l}

where,

E = young modulus of steel = 20\times 10^{10}Pa

F = force exerted by the weight = m g = 25kg\times 9.8m/s^2

l = length of wire = 10 m

A = area of cross section = 1.5\times 10^{-8}m^2

\Delta l = change in length = ?

Putting values in above equation, we get:

20\times 10^{10}=\frac{25\times 9.8\times 10}{1.5\times 10^{-8}\times \Delta l}\\\\\Delta l=1.8375m

Converting above value in mili meters, we use the conversion factor:

1 m = 1000 mm

So, 1.8375 m = 1837.5 mm

Hence, the steel wire will stretch up to 1837.5 mm

4 0
2 years ago
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