I think you forgot to give the options along with the question. I am answering the question based on my knowledge and research. The criteria responsible for deciding whether a heterogeneous mixture is a colloid or a suspension is whether the <span>particles remain suspended for an extended period of time. I hope it helps you.</span>
Answer:
The value of tangential acceleration
40 ![\frac{m}{s^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%20%7D)
The value of radial acceleration ![\alpha_{r} = 80 \frac{m}{s^{2} }](https://tex.z-dn.net/?f=%5Calpha_%7Br%7D%20%3D%2080%20%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%20%7D)
Explanation:
Angular acceleration = 50 ![\frac{rad}{s^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7Brad%7D%7Bs%5E%7B2%7D%20%7D)
Radius of the disk = 0.8 m
Angular velocity = 10 ![\frac{rad}{s}](https://tex.z-dn.net/?f=%5Cfrac%7Brad%7D%7Bs%7D)
We know that tangential acceleration is given by the formula
![r \alpha](https://tex.z-dn.net/?f=r%20%5Calpha)
Where r = radius of the disk
= angular acceleration
⇒
0.8 × 50
⇒
40 ![\frac{m}{s^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%20%7D)
This is the value of tangential acceleration.
Radial acceleration is given by
![\alpha_{r} = \frac{V^{2} }{r}](https://tex.z-dn.net/?f=%5Calpha_%7Br%7D%20%3D%20%5Cfrac%7BV%5E%7B2%7D%20%7D%7Br%7D)
Where V = velocity of the disk = r ![\omega](https://tex.z-dn.net/?f=%5Comega)
⇒ V = 0.8 × 10
⇒ V = 8 ![\frac{m}{s}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bs%7D)
Radial acceleration
![\alpha_{r} = \frac{8^{2} }{0.8}](https://tex.z-dn.net/?f=%5Calpha_%7Br%7D%20%3D%20%5Cfrac%7B8%5E%7B2%7D%20%7D%7B0.8%7D)
![\alpha_{r} = 80 \frac{m}{s^{2} }](https://tex.z-dn.net/?f=%5Calpha_%7Br%7D%20%3D%2080%20%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%20%7D)
This is the value of radial acceleration.
Answer:
1 casparian strips are present in the root of endodermis.
2 the endarch condition is the character fature of stem.
Answer:
Displacement is 50 m
Explanation:
Distance is simply the measurement of the sum of all paths travelled.
Thus, since he swims the 50m length pool 3 times, then the total distance = 50 × 3 = 150 m
Whereas, displacement is the measurement of length of the shortest path from initial point to final point.
In this case initial point to final point is 50m. Thus, the displacement is 50 m
Answer:
The centripetal acceleration of the car is
.
Explanation:
Let the mass of the car, ![m=10^3\ kg](https://tex.z-dn.net/?f=m%3D10%5E3%5C%20kg)
Diameter of the circular path, d = 100 m
Speed of car, v = 20 m/s
Radius, r = 50 m
When an object moves in a circular path, the centripetal acceleration acts on it. It is given by :
![a=\dfrac{v^2}{r}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7Bv%5E2%7D%7Br%7D)
![a=\dfrac{(20\ m/s)^2}{50\ m}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B%2820%5C%20m%2Fs%29%5E2%7D%7B50%5C%20m%7D)
![a=8\ m/s^2](https://tex.z-dn.net/?f=a%3D8%5C%20m%2Fs%5E2)
So, the centripetal acceleration of the car is
. Hence, this is the required solution.