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Oxana [17]
3 years ago
8

C’est un

Physics
1 answer:
agasfer [191]3 years ago
5 0
Bonjour croissant oui oui bonjour france paris baguette oui croissant
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What is defect of vision​
Anuta_ua [19.1K]

Answer:

The vision becomes blurred due to the refractive defects of the eye. There are mainly three common refractive defects of vision. These are (i) myopia or near-sightedness, (ii) Hypermetropia or far – sightedness, and (iii) Presbyopia. These defects can be corrected by the use of suitable spherical lenses.

4 0
3 years ago
The Tambora volcano on the island of Sumbawa, Indonesia has been known to throw ash into the air with a speed of 625 m/s during
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Answer:

About 1-3 km

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5 0
4 years ago
A thin cylindrical shell is released from rest and rolls without slipping down an inclined ramp that makes an angle of 30° with
NNADVOKAT [17]

Answer: 1.59 sec

Explanation:

The kinetic energy contained in the rotation of the cylinder is 1/2 m v^2

The kinetic energy of translation is also 1/2 m v^2

so the total energy is m v^2

The force applied is mg sin (theta)

= m x 9.8 x 1/2

= 4.9 m

Now equate

F x d = m v^2

4.9 m x 3.1 = m v^2

v^2 = 4.9 x 3.1

v = sqrt(4.9 x 3.1) = 3.9 m/s

Acceleration.

V^2 = 2 a s

4.9 x 3.1 = 2 x a x 3.1

4.9 = 2 a

a = 2.45 m/s^2

Time

T = v/a

= 3.9/2.45

= 1.59 sec

6 0
4 years ago
A plane is flying a circular path at a speed of 55.0 m/ s, with a radius of 18.3 m. The centripetal force needed to maintain thi
Nadusha1986 [10]

The plane has a centripetal acceleration <em>a</em> of

<em>a</em> = <em>v</em> ²/<em>r</em>

where <em>v</em> is the plane's tangential speed and <em>r</em> is the radius of the circle. By Newton's second law,

<em>F</em> = <em>mv</em> ²/<em>r</em>

Solve for the mass <em>m</em> :

<em>m</em> = <em>Fr</em>/<em>v</em> ² = (3000 N) (18.3 m) / (55.0 m/s)² ≈ 18.1 kg

7 0
3 years ago
What is the heat needed to raise the temperature of 24.7 kg silver from 14.0 degrees celsius to 30.0 degrees celsius? specific h
Citrus2011 [14]
The amount of heat needed to increase the temperature of a substance by \Delta T is given by
Q=m C_s \Delta T
where
m is the mass of the substance
C_s is its specific heat capacity
\Delta T is the increase of temperature

The sample of silver of our problem has a mass of m=24.7 kg. Its specific heat capacity is C_s = 236 J/g^{\circ}C and the increase in temperature is
\Delta T=30.0^{\circ}-14.0^{\circ}C=16.0^{\circ}C

Therefore, the amount of heat needed is
Q=mC_s \Delta T=(24.7 kg)(236 J/g^{\circ}C)(16.0^{\circ}C)=9.32 \cdot 10^4 J
8 0
4 years ago
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