(1500 rev/min)(min / 60 s) / (3.0 s) = 8.33 rev/s²
<span>(B) </span>
<span>(1/2)(8.33 rev/s²)(3.0 s)² = 37.5 rev </span>
<span>(C) </span>
<span>(1500 rev/min)(min / 60 s)[2π(0.12 m) / rev] = 18.8 m/s</span>
Answer:
if this is on odyssey ware then i can edit my answer to help you
Explanation:
kinematic equation
v=u+at
v-u=at
v-u = 1x5
the driver will have increased speed by 5 m/s. actual speeds unknown
The answer on Edge would be (A.)= Larger and Cooler ! I'm doing the same thing as y'all. Good luck everyone.
We will have that the graph that describes the scenario is given by graph B.
