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Darina [25.2K]
3 years ago
10

Plzz answer this question correctly

Physics
1 answer:
VikaD [51]3 years ago
3 0

Answer:

the acceleration of A is three times that of B

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A simple dipole consists of two charges with the same magnitude, q, but opposite sign separated by a distance d. The EDM (electr
DedPeter [7]

Answer:

a. dW = ∫pEsinθdθ  b. W = p.E

Explanation:

a. We know torque τ = p × E = pEsinθ where θ is the angle between p and E

Let the torque τ rotate the dipole by an amount dθ. So, the workdone dW = ∫τdθ = ∫pEsinθdθ

b. So, the total work done is gotten by integrating from 90 to θ. So,

W = ∫₉₀⁰dW

= ∫₉₀⁰pEsinθdθ

= pE∫₉₀⁰sinθdθ

= pE(cosθ - cos90)

=pEcosθ

= p.E

8 0
3 years ago
Is a projectile motion graph a straight graph or a curved graph<br>​
Usimov [2.4K]

Answer:

» Projectile motion is a curved graph.

☑ This is because projectile motion consists of both vertical and horizontal motion, with one starting angle. Hence as the body starts motion, it is acted upon by gravity.

At point v = 0, the motion is free from gravity hence approaching horizontal motion.

Examples;

  • A ball kicked upwards at an angle which is not 90°
  • A man playing golf.
  • A plane dropping a bomb.

7 0
2 years ago
Read 2 more answers
Does anyone know this
NARA [144]

1) The net force is 16 N to the right

2) The net force is 98 N to the left

3) The net  force is 0.5 N downward

4) The net force is 170 N to the right

5) The net force is 175 N to the  right

Explanation:

1)

To find the net force, we have to analyze all the forces acting on the box.

We have:

  • Force to the right: F_a = 20 N, the applied force
  • Force to the left: F_f = 4 N, the force of friction
  • Force to the bottom: F_g = 400 N, the weight of the box (the weight is always downward vertically)
  • Force to the top: F_N = 400 N. This is the normal force, which is the reaction force exerted by the table on the box: it points upward and counterbalances the weight of the box, preventing it from falling down)

Therefore, the horizontal net force is

F_x = F_a - F_f = 20 - 4 = 16 N (to the right)

While the vertical force is

F_y = F_N - F_g = 400 - 400 = 0

So the net force is 16 N to the right.

2)

In this case, we have the following forces:

  • F_g = 4 N downward, the weight of the ball
  • F_a = 100 N to the left, the force that kicks the ball
  • F_f = 2 N to the right, the force of friction
  • F_N = 4 N upward, the normal reaction exerted by the field on the ball

Therefore, the horizontal net force is

F_x =F_a - F_f = 100 -2 = 98 N (to the left)

While the vertical force is

F_y = F_g - F_N = 4 - 4 = 0 (downward)

And so, the net force is 98 N to the left.

3)

The force acting on the squirrel in this problem are:

  • F_g = 8 N downward, the weight of the squirrel
  • F_f = 7.5 N upward, the air resistance, acting upward

Both forces act vertically and there are no other forces acting in other directions, therefore the net force on the squirrel is simply equal to the net force on the vertical direction, which is:

F_y = F_g - F_f = 8 - 7.5 = 0.5 N

And since the weight is larger than the air resistance, the direction of the net force is downward.

4)

The forces acting on Monkey are:

  • F_1=95 N is the force applied to the right by Bunny
  • F_2 = 75 N is the force applied by Deer from the left (so, also on the right)
  • F_g = 50 N is the weight of Monkey, downward
  • F_N = 50 N is the normal reaction exerted by the surface, upward

So, the net force in the horizontal direction is

F_x = F_1 + F_2 = 95+75=170 N (to the right)

While the net force in the vertical direction is

F_y = F_N - F_g = 50 - 50 = 0

And therefore the net force is 170 N to the right

5)

The forces acting on Deer are:

  • F_a = 100 N + 100 N = 200 N to the right, the combined force applied by Bunny and Monkey
  • F_f = 25 N to the left, the force of friction
  • F_g = 150 N downward, the weight of the deer
  • F_N = 150 N upward, the normal reaction from the surface that balances the weight

So the net horizontal force is

F_x = F_a - F_f = 200 - 25 = 175 N to the right

While the net vertical force is

F_y = F_N - F_g = 150 - 150 = 0

So the net force is 175 N to the right.

Learn more about vector addition:

brainly.com/question/4945130

brainly.com/question/5892298

#LearnwithBrainly

3 0
3 years ago
Use the following equation to help you answer the question. The peak intensity of radiation from a star named Sigma is 2 x 10 6
puteri [66]

Answer:

1449 K

Explanation:

The surface temperature of a star is related to its peak wavelength by Wien's displacement law:

T=\frac{b}{\lambda}

where

T is the surface temperature

b is Wien's displacement constant

\lambda=2\cdot 10^{-6} m

So the surface temperature of the star is

T=\frac{2.898 \cdot 10^{-3} Km}{2\cdot 10^{-6} m}=1449 K

8 0
3 years ago
Read 2 more answers
Worth 50 point!!!
olasank [31]

Answer:

Chief Hopper

Explanation:

Mike travels at a constant speed of 3.1 m/s.  To find how long it takes him to reach the school, we need to find the distance he travels.  We can do this using Pythagorean theorem.

a² + b² = c²

(1000 m)² + (900 m)² = c²

c ≈ 1345 m

So the time is:

v = d / t

3.1 m/s = 1345 m / t

t ≈ 434 s

Next, Chief Hopper travels a total distance of 1900 m, starting at rest and accelerating at 0.028 m/s².  So we can use constant acceleration equation to find the time.

d = v₀ t + ½ at²

1900 m = (0 m/s) t + ½ (0.028 m/s²) t²

t ≈ 368 s

So Chief Hopper reaches the school first, approximately 66 seconds before Mike does.

3 0
3 years ago
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