It is an example of rolling friction because balls roll.
Answer is ROLLING
Answer a would be correct since velocity is a vector and has a magnitude and a direction. In this case v₁ = - v₂.
Answer:
Fractional error = 0.17
Percent error = 17%
F = 112 ± 19 N
Explanation:
Plug in the values to find the force:
F = (3.5 kg) (20 m/s)² / (12.5 m) = 112 N
Find the fractional error:
ΔF/F = Δm/m + 2Δv/v + Δr/r
ΔF/F = 0.1/3.5 + 2(1/20) + 0.5/12.5
ΔF/F = 0.17
Multiply by 100% to find the percent error:
ΔF/F × 100% = 17%
Solve for the absolute error:
ΔF = 0.17 × 112 N = 19 N
Therefore, the force is:
F = 112 ± 19 N
Answer:
3000 N
Explanation:
<em>Newton's second law of motion</em> describes the relationship between an object's mass and the amount of force needed to accelerate it.
This law can be expresses as F=ma,
where
- F - force acting on an object
- m- the mass of an object
- a - its acceleration
The more mass an object has, the more force you need to accelerate it. And the greater the force, the greater the object's acceleration.
<em>F = ma</em>
<em>F = 1000×3 </em>
<em> = 3000 N</em>
911.1×155.9 = 14,202.49
14,202.49 in 3 significant figures would be either 14,200 or 1.42×10^4
