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TEA [102]
3 years ago
10

A scientist is trying to determine whether a newly observed phenomenon can be described as a wave. Which of the following questi

ons would the scientist want to ask about the phenomenon?
A.Can you see it?
B.Does it transfer energy?
C.Is it solid?
D.How quickly does it travel?
Physics
1 answer:
Step2247 [10]3 years ago
7 0

Answer:

B. does it transfer energy

A wave is a disturbance in a medium. Particles vibrate and TRANSFER their ENERGY to their neighbors.

You might be interested in
Every summer I drive to Pennsylvania. It is 895 km to get there. If I average 100 km/hr, how much time will I spend driving?
Ivan

Answer the time you bee spending driving iss 795 because 895-795=100

Explanation:

6 0
2 years ago
In order to find the resultant of two vectors we must use the pythagoran therom, a +b2-2. Where the crepresents the resultant ve
nadezda [96]

Answer:

Furthermore, the Pythagorean theorem works when the two added vectors are at right angles to one another - such as for adding a north vector and an east vector.

8 0
3 years ago
Convert 463.833 m/s to km/ min
Alexus [3.1K]

Answer:

27.82998 km/min

Explanation:

To convert m/sec into km/hr, multiply the number by 18 and then divide it by 5.

8 0
3 years ago
A hockey puck has a coefficient of kinetic friction of μk = .35. If the puck feels a normal force (FN) of 5 N, what is the frict
alina1380 [7]

Answer:

The frictional force is  F_f =  1.75 \  N

Explanation:

From the question we are told that

     The coefficient of kinetic force is  μk = 0.35

     The normal force felt by the puck is  F_N  =  5 \  N

Generally the frictional force that acts on the puck is mathematically represented as

          F_f =  \mu_k  *  F_N

=>       F_f =  0.35  *  5

=>       F_f =  1.75 \  N

3 0
3 years ago
A bullet glider and a target glider both have a mass of 0.200 kg. The bullet glider is moving 0.450 m/s
Romashka [77]

Answer:

the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.

Explanation:

When the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.

Changes can occur that the gliders unite and move with a cosecant speed less than the initial one.

The whole process must be analyzed using conservation of the moment.

             p₀ = m v₀

celestines que clash case

             p_f = (m + M) v

             po = pf

             m v₀ = (n + M) v

             v = \frac{m}{m+M}

calculemos

            v= \frac{0.200}{0.200+M} 0.450

            v= 0.09 m/s

elastic shock case

           p₀ = m v₀

           p_f = m v₁ +M v₂

           p₀ = p_f

           m v₀ = m v₁ + m v₂

6 0
3 years ago
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