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TEA [102]
2 years ago
10

A scientist is trying to determine whether a newly observed phenomenon can be described as a wave. Which of the following questi

ons would the scientist want to ask about the phenomenon?
A.Can you see it?
B.Does it transfer energy?
C.Is it solid?
D.How quickly does it travel?
Physics
1 answer:
Step2247 [10]2 years ago
7 0

Answer:

B. does it transfer energy

A wave is a disturbance in a medium. Particles vibrate and TRANSFER their ENERGY to their neighbors.

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_____ is a device
erastovalidia [21]

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transformers

Explanation:

A transformer is a device that increases or decreases voltage.

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1 year ago
When is the universal theme of a story often revealed?
elena-14-01-66 [18.8K]
It is often revealed <span>at the resolution of the story, when the reader can see how the story ends.</span>
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WHAT SHOULD I NAME MY DEAD RAT?
olga_2 [115]

Answer:

pablito

Explanation:

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2 years ago
A heat engine running backward is called a refrigerator if its purpose is to extract heat from a cold reservoir. The same engine
Goryan [66]

Answer:

a) 2.85 kW

b) $ 432

c) $ 76.95

Explanation:

Average price of electricity = 1 $/40 MJ

Q = 20 kW

Heat energy production = 20.0 KJ/s

Coefficient of performance,  K = 7

also

K=(QH)/Win

Now,

Coefficient of Performance, K = (QH)/Win = (QH)/P(in) = 20/P(in) = 7

where

P(in) is the input power

Thus,

P(in) = 20/7 = 2.85 kW

b) Cost = Energy consumed × charges

Cost = ($1/40000kWh) × (16kW × 300 × 3600s)

cost = $ 432

c) cost = (1$/40000kWh) × (2.85 kW × 200 × 3600s) = $76.95

4 0
2 years ago
At the same moment, one rock is dropped and one is thrown downward with an initial velocity of 29m/s from the top of a building
Inessa [10]

Answer:

The thrown rock strike 2.42 seconds earlier.

Explanation:

This is an uniformly accelerated motion problem, so in order to find the arrival time we will use the following formula:

x=vo*t+\frac{1}{2} a*t^2\\where\\x=distance\\vo=initial velocity\\a=acceleration

So now we have an equation and unkown value.

for the thrown rock

\frac{1}{2}(9.8)*t^2+29*t-300=0

for the dropped rock

\frac{1}{2}(9.8)*t^2+0*t-300=0

solving both equation with the quadratic formula:

\frac{-b\±\sqrt{b^2-4*a*c} }{2*a}

we have:

the thrown rock arrives on t=5.4 sec

the dropped rock arrives on t=7.82 sec

so the thrown rock arrives 2.42 seconds earlier (7.82-5.4=2.42)

6 0
2 years ago
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