What is the ability of the body to function successfully and efficiently during

Why don’t we feel the gravitational force of a large object such as a skyscraper semi-truck?

Kobotan [32]

Answer:

Se the explanation below

Explanation:

We do not feel these forces of these bodies, because they are very small compared to the force of Earth's attraction. Although its mass is greater than that of a human being, its mass is not compared to the Earth's mass. In order to understand this problem we will use numerical data and the universal gravitation formula, to give validity to the explanation.

Force exerted by the Earth on a human being

$F=G*\frac{m_{1}*m_{2}}{r^2}$

Where:

G = universal gravitation constant = 6.673*10^-11 [N*m^2/kg^2]

m1 = mass of the person = 80 [kg]

m2 = mass of the earth 5.97*10^24[kg]

r = distance from the center of the earth to the surface or earth radius = 6371 *10^3 [m]

Now replacing we have

$F = 6.673*10^{-11} *\frac{80*5.97*10^{24}}{(6371*10^{3})^{2} } \\F = 785[N]$

Force exerted by a building on a human being

Where:

G = universal gravitation constant = 6.673*10^-11 [N*m^2/kg^2]

m1 = mass of the person = 80 [kg]

m2 = mass of the earth 300000 [ton] = 300 *10^6[kg]

r = distance from the building to the person = 2[m]

$F = 6.673*10^{-11}*\frac{80*300*10^6}{2^{2} } \\F= 0.4 [N]$

As we can see the force exerted by the Earth is 2000 times greater than that exerted by a building with the proposed data.

8 0

3 years ago

According to quantum physics, measuring velocity of a tiny particle with an electromagnet

lidiya [134]

Answer:

Option A.

Explanation:

In quantum physics there is a law to relate the position and the momentum of the particle, it says that if we know with precision where is a quantum particle, we can not know the momentum of this particle, in other words, the velocity of the particle. So, when we measure the velocity of the particle we find the correct value of the particle, but we can not determine with accuracy where is the particle. This law is known as the Heisenberg's uncertainty principle and, its expressed as follows:

$\Delta x \Delta p \geq \frac{h}{4 \pi}$

where Δx: is the position's uncertainty, Δp: is the momentum's uncertainty and h: is the Planck constant.

Therefore, the correct answer is A: measuring the velocity of a tiny particle with an electromagnet has no effect on the velocity of the particle. It only affects the determination of the particle's position.

I hope it helps you!

4 0

3 years ago

A 1000 kg rocket ship is traveling at 40 m/s. If the velocity changes to 70

nydimaria [60]

Answer: A

Explanation:

6 0

3 years ago

A retail gasoline pump is able to fill a 14.0 gallon automobile tank in 1.50 minutes. What is the mass flow rate deliverd by the

Ludmilka [50]

We have volume of gasoline = 14.0 gallon