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2 years ago

Can you help pls i rlly need help

Mathematics

2 answers:

n200080 [17]2 years ago

6 0

For the first question the equation would be 200 + 50x

The second equation should be
200 + 50(1) = 250

Rudik [331]2 years ago

5 0

Answer:

200+50x = first month

50x (x represents number of months)

First month is 200+5=$250

Step-by-step explanation:

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Atticus wants to buy 2/3 of a square yard of wrapping paper the paper cost $2.40 per yard how much will Atticus spend on wrappin

balu736 [363]

Atticus will spend $1.60 on wrapping paper.

Step-by-step explanation:

Given,

Cost of paper per yard = $2.40

Atticus wants to buy = 2/3

Cost of 2/3 yards of paper = $\frac{2}{3}*2.40$

Cost of 2/3 yards of paper = $\frac{4.80}{3}$

Cost of 2/3 yards of paper = $1.60

Atticus will spend $1.60 on wrapping paper.

Keywords: division, fraction

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3 0

3 years ago

How do I solve this finding the first four of the sequence?

Gemiola [76]

Answer:

300,350,400,450

Step-by-step explanation:

the formula for any n term is:

tn=a1+(n-1)d

t1= 300+(1-1)d=300

t2= 300+(2-1)50= 350

t3= 300+(3-1)50= 400

t4= 300+(4-1)50 = 450

and so on...

5 0

2 years ago

The accompanying summary data on total cholesterol level (mmol/l) was obtained from a sample of Asian postmenopausal women who w

dimulka [17.4K]

Answer:

99% CI:

$-4.637\leq\mu_v-\mu_o\leq 3.737$

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}$

The MSE can be calculated as

$MSE=\frac{(SSE_1+SSE_2)}{df} =\frac{(n_1s_1)^2+(n_2*s_2)^2}{n_1+n_2-2}\\\\MSE=\frac{(85*1.05)^2+(96*1.20)^2}{85+96-2}=\frac{7965.56+13272.04}{179} =118.65$

The weighted sample size nh can be calculated as

$n_h=\frac{2}{1/n_1+1/n_2}=\frac{2}{1/85+1/96}=\frac{2}{0.0222} =90.16$

The standard deviation then becomes

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}=\sqrt{\frac{2*118.65}{90.16}}=\sqrt{2.632} =1.623$

The z-value for a 99% confidence interval is z=2.58.

The difference between means is

$\Delta M=M_v-M_o=5.10-5.55=-0.45$

Then the confidence interval can be constructed as

$\Delta M-z*s_{Md}\leq\mu_v-\mu_o\leq \Delta M+z*s_{Md}\\\\ -0.45-2.58*1.623\leq\mu_v-\mu_o\leq -0.450+2.58*1.623\\\\-0.450-4.187\leq\mu_v-\mu_o\leq-0.450+4.187\\\\-4.637\leq\mu_v-\mu_o\leq 3.737$

8 0

2 years ago

what is the theoretical probability tha a physics teacher will give you homework at the end of a lesson

fomenos

I think 3 but let me know

3 0

2 years ago

The school cafeteria serves tacos every 60 and cheeseburgers every eighth day.If tacos and cheeseburgers are both on today's men

Ad libitum [116K]

Answer:

120 days

Step-by-step explanation:

Tacos are served every 60 days.

Cheeseburgers are served every 8 days.

Since, both Cheeseburgers and Tacos are served today, the next day on which both will be served is gotten by finding the Lowest Common Multiple of 60 and 8.

To find the LCM,

First, we express the numbers as a product of their prime factors.

60= 2X2X3X5=2²X3X5

8=2X2X2=2³

Next, we take each of the term with the highest power and multiply.

L.C.M = 2³X3X5=120

After 120 days, Cheeseburgers and Tacos will be served on the same day.

5 0

2 years ago