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3 years ago

What other kinds of allotropes are there? What kinda of properties and atomic bonds do they have?

Chemistry

1 answer:

Cloud [144]3 years ago

7 0

Diamond and <span>Graphite are some allotropes.

btw love your icon of Harry :)</span>

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A group 2 metal carbonate has a mass of 84 g/mol. Identify the group 2 metal X using its chemical formula.

zepelin [54]

Answer:

Magnesium

0.003mole

Explanation:

The problem here entails we find the metal in the carbonate.

For group 2 member, let the metal = X;

The carbonate is XCO₃;

If we sum the atomic mass of the elements in the metal carbonate, we should arrive at 84g/mol

Atomic mass of C = 12g/mol

O = 16g/mol

Atomic mass of X + 12 + 3(16) = 84

Atomic mass of X = 84 - 60 = 24g/mol

The element with atomic mass of 24g is Magnesium

Number of moles in 0.3g of CaCO₃:

Molar mass of CaCO₃ = 40 + 12 + 3(16) = 100g/mol

Number of moles = $\frac{mass}{molar mass}$

Number of moles = $\frac{0.3}{100}$ = 0.003mole

7 0

3 years ago

Visible light is an example of

Svetradugi [14.3K]

Answer:

electromagnetic energy.

Explanation:

please mark brainliest

3 0

3 years ago

Read 2 more answers

In the reaction of aluminum bromide with ionized sodium bromide which compoiund is the lewis acid

murzikaleks [220]

The answer is A) Aluminum Bromide
hope this helps :)

3 0

2 years ago

Read 2 more answers

I NEED HELP PLEASE, THANKS! :)

krok68 [10]

Answer:

$\large \boxed{\text{2.20 g Pb}}$

Explanation:

They gave us the masses of two reactants and asked us to determine the mass of the product.

This looks like a limiting reactant problem.

1. Assemble the information

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ: 239.27 32.00 207.2

2PbS + 3O₂ ⟶ 2Pb + 2SO₃

m/g: 2.54 1.88

2. Calculate the moles of each reactant

$\text{Moles of PbS} = \text{2.54 g PbS } \times \dfrac{\text{1 mol PbS}}{\text{239.27 g PbS}} = \text{0.010 62 mol PbS}\\\\\text{Moles of O}_{2} = \text{1.88 g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.058 75 mol O}_{2}$

3. Calculate the moles of Pb from each reactant

$\textbf{From PbS:}\\\text{Moles of Pb} = \text{0.010 62 mol PbS} \times \dfrac{\text{2 mol Pb}}{\text{2 mol PbS}} = \text{0.010 62 mol Pb}\\\\\textbf{From O}_{2}:\\\text{Moles of Pb} =\text{0.058 75 mol O}_{2} \times \dfrac{\text{2 mol Pb}}{\text{3 mol O}_{2}}= \text{0.039 17 mol Pb}\\\\\text{PbS is the $\textbf{limiting reactant}$ because it gives fewer moles of Pb}$

4. Calculate the mass of Pb

$\text{ Mass of Pb} = \text{0.010 62 mol Pb} \times \dfrac{\text{207.2 g Pb}}{\text{1 mol Pb}} = \textbf{2.20 g Pb}\\\\\text{The reaction produces $\large \boxed{\textbf{2.20 g Pb}}$}$

5 0

3 years ago

An atom's mass number equals the number of

torisob [31]

The total number of protons and neutrons

4 0

3 years ago