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hammer [34]
3 years ago
8

Fructose is an example of a ketohexose. The -hexose part of the name indicates that fructose is a Choose... that contains Choose

... carbons. The keto- part of the name indicates that fructose contains Choose... functional group. Fructose can combine with glucose to form sucrose. Therefore, sucrose is a Choose... .
Chemistry
1 answer:
Vikki [24]3 years ago
5 0

Answer:

carbohydrate, 6, a carbonyl, disaccharide

Explanation:

Fructose is an example of a ketohexose. The -hexose part of the name indicates that fructose is a carbohydrate that contains 6 carbons. <em>There are more isomers that are ketohexoses.</em>

The keto- part of the name indicates that fructose contains a carbonyl functional group. <em>In ketones, the carbonyl is in an inner carbon.</em>

Fructose can combine with glucose to form sucrose. Therefore, sucrose is a disaccharide. <em>Disaccharides are formed by the bonding of 2 monosaccharides.</em>

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The equilibrium constant, K., for the following reaction is 83.3 at 500 K. PC13(g) + Cl2(g) = PC13(E) Calculate the equilibrium
lord [1]

Answer:

The equilibrium concentration of PCl_5=0.228 M.

The equilibrium concentration of PCl_3=0.280 M -0.228 M=0.052M.

The equilibrium concentration of Cl_2=0.280 M -0.228 M=0.052M.

Explanation:

Answer:

The equilibrium concentration of HCl is 0.01707 M.

Explanation:

Equilibrium constant of the reaction = K_c=83.3

Moles of PCl_3 = 0.280 mol

Concentration of  [PCl_3]=\frac{0.280 mol}{1.00 L}=0.280 M

Moles of Cl_ = 0.280 mol

Concentration of [Cl_2]=\frac{0.280 mol}{1.00 L}=0.280M

           PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

Initial:            0.280      0.280                            0

At eq'm:         (0.280-x)   (0.280-x)                     x

We are given:

[PCl_3]_{eq}=(0.280-x)

[Cl_2]_{eq}=(0.280-x)

[PCl_5]_{eq}=x

Calculating for 'x'. we get:

The expression of K_{c} for above reaction follows:

K_c=\frac{[PCl_5]}{[PCl_3][Cl_2]}

Putting values in above equation, we get:

83.3=\frac{x}{(0.280-x)\times (0.280-x)}

On solving this quadratic equation we get:

x = 0.228, 0.344

0.228 M < 0.280 M< 0.344 M

x = 0.228 M

The equilibrium concentration of PCl_5=0.228 M.

The equilibrium concentration of PCl_3=0.280 M -0.228 M=0.052M.

The equilibrium concentration of Cl_2=0.280 M -0.228 M=0.052M.

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navik [9.2K]

Answer:

A. The muscle would not contract.

Explanation:

The sarcoplasmic reticulum is a specialized smooth endoplasmic reticulum that transmits electrical impulses and is the primary regulator of calcium storage, release, and reuptake. On the other hand, glycolysis and the mitochondria are responsible for cellular ATP production.

In the muscle, the SR and mitochondrial function are interconnected, ATP is used to lower myoplasmic calcium levels during muscle relaxation, this means that muscle contractility is linked to the control of sarcomeric Ca2+ delivery/removal and ATP generation/utilization.<em> If we have a failure to remove Ca2+ from the cytosol by not producing ATP, the muscle will be prevented from relaxation, subsequently there will be a decrease in muscle contraction too.</em>

I hope you find this information useful and interesting! Good luck!

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