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2 years ago

15

A rocket takes off from Earth and starts flying to Mars. What happens to the force of gravity between the rocket and Earth as th

e rocket approaches Mars

1 answer:

lawyer [7]2 years ago

5 0

The force of gravity between Earth and Mars will decrease.

The gravitational law is given as-

F = G mM/r²

here, m= mass of rocket

M = mass of earth

r = distance between earth and rocket

So, as rocket takes off from earth and fly towards mars then the distance starts to increase between earth and rocket, and the gravitational pull between them starts to weaken. Then a point will reach when rocket will far from gravity of earth and could probably enter the gravity of Mars.

Learn more about gravitational law here:

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Blue to gray in color and reaching up to 10 feet (3.05 meters) in length and 220 pounds (99.8 kilograms) in weight, the sailfish

vagabundo [1.1K]

Answer:

the distance traveled by the fish is 3648 m

Explanation:

In general, animals have a small period of acceleration, which we will despise after which they travel at a constant speed so we can use the kinematic equations in uniform motion

We reduce the units to System SI

t = 2 min (60s / 1 min) = 120 s

Calculate

V = x / t

x= V t

x = 30.4 120

x = 3648 m

This is the distance traveled by the fish

6 0

3 years ago

DNA is coiled into chromosomes in a cell's

tia_tia [17]

Answer: Cell's nucleus

Explanation :

The full form of DNA is Deoxyribonucleic acid. The genetic information of a cell is organized in the DNA. It is inherited from parents by their children.

DNA is coiled into chromosomes in a cell's nucleus. It has a shape like a double helix. It is twisted in the form of spirals.

Hence, DNA is coiled into chromosomes in a cell's Nucleus.

6 0

3 years ago

Read 2 more answers

If two normal distributions each have the same mean, but one has a standard deviation of 1 and the other has a standard deviatio

likoan [24]

In comparison to a distribution with a standard deviation of 5, one has a curve with a higher peak. The variability will be greater the larger the standard deviation. It denotes increased variability in a distribution with a standard deviation of 5.

<h3>What do you mean by the term standard deviation?</h3>

The term "standard deviation" (or "") refers to a measurement of the data's dispersion from the mean. A low standard deviation implies that the data are grouped around the mean, whereas a large standard deviation shows that the data are more dispersed. In contrast, a high or low standard deviation indicates that the data points are, respectively, above or below the mean. A standard deviation that is close to zero implies that the data points are close to the mean. the curve at the top is more dispersed and has a greater standard deviation than the curve at the bottom, which is more concentrated around the mean and has a lower standard deviation.

To learn more about standard deviation, Visit:

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8 0

1 year ago

1. Bone has a Young’s modulus of about

Blababa [14]

#1

As we know that

$Y = \frac{stress}{strain}$

now plug in all data into this

$1.8\times 10^{10} = \frac{1.68 \times 10^8}{strain}$

$strain = 9.33 \times 10^{-3}$

now from the formula of strain

$strain = \frac{\Delta L}{L}$

$9.33 \times 10^{-3} = \frac{\Delta L}{0.54}$

$\Delta L = 5.04 \times 10^{-3} m$

$\Delta L = 5.04 mm$

#2

As we know that

pressure * area = Force

here we know that

$Area = 3.53 \times 11.6 = 40.95 m^2$

$P = 0.2 atm = 0.2 \times 1.01 \times 10^5 = 2.02\times 10^4 Pa$

now force is given as

$F = 40.95 \times (2.02\times 10^4) = 8.27 \times 10^5 N$

#3

As we know that density of water will vary with the height as given below

$\rho = \frac{\rho_0}{1 - \frac{\Delta P}{B}}$

here we know that

$\Delta P = 2600 atm = 2600 \times 1.01 \times 10^5 = 2.63\times 10^8 Pa$

$B = 2.3 \times 10^9 N/m^2$

now density is given as

$\rho = \frac{1050}{1 - \frac{2.63\times 10^8}{2.3 \times 10^9}}$

$\rho = 1185.3 kg/m^3$

#4

as we know that pressure changes with depth as per following equation

$P = P_o + \rho g h$

here we know that

$P = 3 P_0$

now we will have

$3P_0 = P_0 + \rho g h$

$2P_0 = \rho g h$

$2(1.01 \times 10^5) = 1025 (9.81)(h)$

here we will have

$h = 20.1 m$

so it is 20.1 m below the surface

#5

Here net buoyancy force due to water and oil will balance the weight of the block

so here we will have

$mg = \rho_1V_1g + \rho_2V_2g$

$A(0.0476)979 = 922(A)(0.0476 - x) + 1000(A)(x)$

$46.6 = 43.89 - 922x + 1000x$

$x = 3.48 cm$

so it is 3.48 cm below the interface

5 0

3 years ago

A clarinetist, setting out for a performance, grabs his 3.010 kg clarinet case (including the clarinet) from the top of the pian

KATRIN_1 [288]

Answer:

-0.481 m/s^2

Explanation:

The force equation of this problem is given as:

F - W = ma

where F = upward force holding the clarinet bag

W = downward force (weight of the clarinet)

The mass of the clarinet bag is 3.010 kg, therefore, its weight is:

W = mg

W = 3.010 * 9.8 = 29.498

F = 28.05 N

Therefore:

28.05 - 29.498 = 3.010 * a

-1.448 = 3.010a

=> a = -1.448 / 3.010

a = -0.481 m/s^2

The acceleration of the bag is downward.

8 0

3 years ago