<h2>
The seagull's approximate height above the ground at the time the clam was dropped is 4 m</h2>
Explanation:
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 0 m/s
Acceleration, a = 9.81 m/s²
Time, t = 3 s
Substituting
s = ut + 0.5 at²
s = 0 x 3 + 0.5 x 9.81 x 3²
s = 44.145 m
The seagull's approximate height above the ground at the time the clam was dropped is 4 m
Answer:
35.625° C
Explanation:
See attachment
a) Final temperature is 35.625° C
b) 0°
Answer:
42.5mph
Explanation:
The computation of the average speed is shown below:
As we know that
Speed = Distance ÷ Time
ANd, distance = Speed × time
So, the distance would be
= (50 × 5 hours) + (30 × 3)
= 250 + 90
= 340 miles
And, the total time taken is 8 hours
So, the average speed is
= 340 miles ÷ 8 hours
= 42.5mph
