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Anna11 [10]
3 years ago
8

A bicycle pump contains 20 cm3 of air at a pressure of 100 kPa. The air is then pumped in a tyre of volume 100 cm3. Calculate th

e pressure of the air in the tyre. Assume that the temperature is fixed. ​
Physics
1 answer:
Natasha2012 [34]3 years ago
7 0

Answer:

The pressure of the air in the tyre is 20 kPa

Explanation:

The parameters for the bicycle pump and tyre are;

The volume of air contained in the bicycle pump, V₁ = 20 cm³

The pressure of the air contained in the bicycle pump, P₁ = 100 kPa

The volume (available) of the tyre, where the air is pumped, V₂ = 100 cm³

Let P₂ represent the pressure in the tyre after the air is pumped

By Boyle's law, we have that at constant temperature, the volume of a given mass of gas is inversely proportional to its pressure;

Mathematically, Boyle's law gives the following equation;

P₁ × V₁ = P₂ × V₂

∴ P₂ = (P₁ × V₁)/V₂

Substituting the known values gives;

P₂ = (100 kPa × 20 cm³)/(100 cm³)

∴ P₂ = 100 kPa × 1/5 = 20 kPa

P₂ = 20 kPa

The pressure of the air in the tyre = P₂ = 20 kPa.

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236.3  x 10^-^3 C

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Also, flux is equal to the magnetic field multiplied with the area of the coil

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The gauge pressure in the tires of your car is 210 kPa (30.5 psi) when the temperature is 25°C (77 °F). Several days later it is
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P = 311.325kPa (add 101.325 to change gauge pressure to absolute pressure)

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Final P and T values:

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Set the initial and final P/T values equal to each other and solve for the final P:

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Subtract 101.325kPa to find the final gauge pressure:

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