$\tan x = \dfrac{\text{Opposite}}{\text{Adjacent}}\\\\\implies \tan x = \dfrac{12}{6}\\\\\implies \tan x = 2\\\\\implies x = \tan^{-1} (2)=63.4^\circ$

8 0

3 years ago

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Divide the following

vampirchik [111]

$\frac{x^{2} - 4}{x - 8} \div \frac{x - 2}{1}$
$\frac{x^{2} + 2x - 2x - 4}{x - 8} \div \frac{x - 2}{1}$
$\frac{x(x) + x(2) - 2(x) - 2(2)}{x - 8} \div \frac{x - 2}{1}$
$\frac{x(x + 2) - 2(x + 2)}{x - 8} \div \frac{x - 2}{1}$
$\frac{(x - 2)(x + 2)}{x - 8} \div \frac{x - 2}{1}$
$\frac{x - 2}{x - 8}$

The answer is C.

7 0

4 years ago

20 &21 pleaseee 15 points

VashaNatasha [74]

Answer:

20. is B (second one)

21. is A (first one)

Step-by-step explanation:

8 0

3 years ago

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