Answer:
301.8 g
Explanation:
We prepare a solution with 200.4 g of water (solvent) and 101.42 g of salt (solute). The mass of the solution is equal to the sum of the mass of the solvent and the mass of the solute.
m(solution) = m(solute) + m(solvent)
m(solution) = 200.4 g + 101.42 g
m(solution) = 301.8 g (we round-off to one decimal according to the significant figures rules)
Its quite alot of work, but here it is....
1. Silver Nitrate: AgNO3 (aq)
<span>Potassium Chloride: KCl </span>
<span>To do a double replacement reaction, switch the two metals around, in this case Silver and Potassium so you are left with: </span>
<span>Potassium Nitrate: KNO3 </span>
<span>Silver Chloride: AgCl </span>
<span>The chemical equation should be something like this: </span>
<span>AgNO3 (aq) + KCl => KNO3 + AgCl
</span>
2The chemical reaction is as follows:Al2(SO4)3 + 3Ca(OH)2 → 3CaSO4 + 2Al(OH)3 Explanation:1mol of Al2(SO4)3 will react with 3mol Ca(OH)2 to produce 3mol CaSO4 and 2 mol Al(OH)3.First we have to find the number of moles of Al2(SO4)3 :Number of moles = Mass/ Molar massMass of Al2(SO4)3 = 500gMolar mass of Al2(SO4)3 = 342.15 g/molNumber of moles = 500/342.15Number of moles = 1.461 mol Al2(SO4)3Multiplying the coeffecient of Ca(OH)2 with 1.461:= 3*1.461 = 4.383 mol Ca(OH)2 Now we have to find the number of moles of Ca(OH)2:Mass of Ca(OH)2 = 450gMolar mass of Ca(OH)2 = 74.09 g/mol Number of moles = 450/74.09Number of moles = 6.074 mol Ca(OH)2We need 4.383mol to react completely with the Al2(SO4)3, so the Ca(OH)2 is in excess, and the Al2(SO4)3 is the limiting reactant. Excess unreacted: 6.074-4.383 = 1.69mol Ca(OH)2 unreacted
You need to add the last substance to the products side(the right sode of the arrow). You have hydrogen and oxygen - water.
You get: BrO3 + N2H4 -> Br2 + N2 + H2O
# of Br: 1x1 = 1 # of Br: 2x1 = 2
O: 3x1 = 3 O: 1x1 = 1
N: 2x1 = 2 B N: 2x1 = 2
H: 4x1 = 4. H: 2x1 = 2
Br:
Multiply the reactant (left) side by 2 to balance.
O:
You've just multiplied the reactant oxygen by 2 so now the reactant side equals 6. Multiply the product (right) side by six as well.
H:
The product side is now equal to 12. Multiply the reactant side by 3 to balance.
N:
Now you have to balance N because the reactant side has been risen. So multiply the product side by three as well.
You end up with the complete and balanced equation:
2BrO3 + 3N2H4 -> Br2 + 3N2 + 6H2O
Integumentary<span> is the organ system that protects the body from various kinds of damage. </span>