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3 years ago

So im confused i don't know what im supposed to do here

Chemistry

2 answers:

larisa [96]3 years ago

8 0

Answer:

save your notes in a google drive folder then go back to canvas and click on the "google drive" tab then scroll down and once you see the name of the folder you saved your notes in, click on it then hit submit

Explanation:

FromTheMoon [43]3 years ago

3 0

So I believe you are supposed to take notes based on the guiding questions (the questions on the side).

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What is the balanced net ionic equation including phases for K2SO4 and SrI2

Triss [41]

Answer:

Sr 2+(aq) + SO42-(aq) → SrSO4(s)

Explanation:

Step 1: Write a properly balanced equation with states:

K2SO4(aq) + Srl2(aq) → 2KI(aq) + SrSO4(s)

Step 2: write the full ionic equation with states. Remember to keep molecules intact. Only states (aq) will dissociate, (s) will not dissociate . This means SrSO4 won't dissociate.

2K+(aq) + SO42-(aq) + Sr 2+(aq) + 2I-(aq) → 2K+(aq) + 2I-(aq) + SrSO4(s)

Step 3: Balanced net ionic equation

Sr 2+(aq) + SO42-(aq) → SrSO4(s)

3 0

3 years ago

Is sliver or aluminum most often used in magnets

dedylja [7]

Neither of them are used in magnets they don’t attract metal

6 0

3 years ago

Most modern medications are given in doses of milligrams. Thyroid medications, however, are typically given in doses of microgra

leonid [27]

Answer:

0.125 mg

Explanation:

The correct answer would be 0.125 mg

According to the conversion factor, one milligram of a sample is equivalent to one thousand micrograms of the same sample.

milligram = $10^{-3}$

microgram = $10^{-6}$

Hence,

1 milligram = 1000 micrograms or 1 microgram = $10^{-3}$ milligram

Therefore, 125 micrograms will be:

125/1000 = 0.125 milligram

4 0

3 years ago

Britney added 0.05 moles of copper(II) nitrate solution to 0.1 moles of sodium hydroxide solution and

Rama09 [41]

The percent yield of copper hydroxide is 84%

<h3>Stoichiometry</h3>

From the question, we are to determine the percent yield of copper hydroxide

First, we will determine the theoretical mass

From the given balanced chemical equation, we have

Cu(NO₃)₂ + 2NaOH -- Cu(OH)₂ + 2NaNO₃

This means,

1 mole of copper(II) nitrate reacts with 2 moles of sodium hydroxide to produce 1 mole of copper hydroxide

Therefore,
0.05 mole of copper(II) nitrate reacts with 0.1 mole of sodium hydroxide to produce 0.05 mole of copper hydroxide

The theoretical number of moles of copper hydroxide that is produced is 0.05 mole

Now, for the theoretical mass

Using the formula,

Mass = Number of moles × Molar mass

Molar mass of copper hydroxide = 97.56 g/mol

Then,

Theoretical mass = 0.05 × 97.56

Theoretical mass of copper of hydroxide produced is = 4.878 g

Now, for the percent yield of copper hydroxide

Percent yield is given by the formula,

$Percent\ yield = \frac{Actual\ yield}{Theoretical\ yield} \times 100\%$

Then,

$Percent\ yield\ of\ copper\ hydroxide= \frac{4.1}{4.878}\times 100\%$

$Percent\ yield\ of\ copper\ hydroxide= 84\%$

Hence, the percent yield of copper hydroxide is 84%.

Learn more on Stoichiometry here: brainly.com/question/9372758

7 0

3 years ago

using the Bohr model for hydrogen: energy = hc/wavelength = 2.18 x 10^-18 Joules (1/nf2 - 1/ni2) N=15 to n=5

soldier1979 [14.2K]

Answer:

Energy lost is 7.63×10⁻²⁰J

Explanation:

Hello,

I think what the question is requesting is to calculate the energy difference when an excited electron drops from N = 15 to N = 5

E = hc/λ(1/n₂² - 1/n₁²)

n₁ = 15

n₂ = 5

hc/λ = 2.18×10⁻¹⁸J (according to the data)

E = 2.18×10⁻¹⁸ (1/n₂² - 1/n₁²)

E = 2.18×10⁻¹⁸ (1/15² - 1/5²)

E = 2.18×10⁻¹⁸ ×(-0.035)

E = -7.63×10⁻²⁰J

The energy lost is 7.63×10⁻²⁰J

Note : energy is lost / given off when the excited electron jumps from a higher energy level to a lower energy level

5 0

3 years ago