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3 years ago

Determine which elements or compounds are products in the follow reaction equation: C+H2+O2→C6H12O2

Chemistry

1 answer:

Keith_Richards [23]3 years ago

4 0

Answer:

C6H12O6 is the product.

Explanation:

As C6H12O6 is on the right side of the arrow, it indicates that C, H2, and O2 are all reacting with each other to produce (or form) C6H12O6. This means that C6H12O6 is the product in this specific reaction.

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Imagine that hotter magma is lying beneath an area of cooler magma deep in the mantle. What do you predict will happen?

allsm [11]

Answer:

it will explod because off all of the prussere but on to it.

Explanation:

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3 years ago

Which of Graphs 1 correctly represents the relationship between the pressure and volume of a gas?

Alborosie

Answer:

Explanation:

pressure is inversely proportional to gas volume

4 0

2 years ago

How many moles of nitrous oxide gas (N2O) is contained in 20.0 L balloon at a pressure of 1.09 atm and a temperature of 298K? Ro

prohojiy [21]

Answer:

There are 0,89 moles of nitrous oxide gas in the balloon.

Explanation:

We apply the formula of the ideal gases, we clear n (number of moles); we use the ideal gas constant R = 0.082 l atm / K mol:

PV= nRT ---> n= PV/RT

n= 1,09 atm x 20,0 L /0.082 l atm / K mol x 298 K

7 0

3 years ago

The daily production of carbon dioxide from an 780.0 mw coal-fired power plant is estimated to be 3.3480 x 104 tons (not metric)

valkas [14]

The production of $CO_{2}$ is $3.3480\times 10^{4} tons/day$ . Converting mass into kg,

1 ton=907.185 kg, thus,

$3.3480\times 10^{4} tons=3.037\times 10^{7} kg$

Thus, production of $CO_{2}$ will be $3.037\times 10^{7} kg/ day$ .

The specific volume of $CO_{2}$ is $0.0120 m^{3}/kg$ .

Volume of $CO_{2}$ produced per day can be calculated as:

$V=Specific volume\times mass$

Putting the values,

$V=0.0120 m^{3}/kg\times 3.037\times 10^{7} kg=364440 m^{3}/day$

Thus, volume of $CO_{2}$ produced per year will be:

$V=\frac{365 days}{1 year}(364440 m^{3}/day)=1.33\times 10^{8}m^{3}/year$

Thus, in 4 year volume of $CO_{2}$ produced will be:

$V=1.33\times 10^{8}m^{3}/year\times 4 years=5.32\times 10^{8}m^{3}$

8 0

3 years ago

The amount of carbon dioxide (in pounds per 15,000 cubic miles) released by a certain SUV depends on its fuel efficiency accordi

Shtirlitz [24]

Answer:

30 miles per gallon.

Explanation:

See picture

When the amount of carbon is plotted based on efficiency, the following graph is obtained (see image)

when looking at the graph, it can be seen that the point of lowest emission is presented with the maximum possible efficiency, 30 miles per gallon and this value is 10400 pounds per 15000 cubic miles.

$W=32x^{2}-2080x+44000$

5 0

4 years ago