The acceleration of a car that starts at 12.5 m/s and reaches 25.5 m/s in 5.00 seconds is 2.6m/s².
<h3>How to calculate acceleration?</h3>
The acceleration of a moving object can be calculated using the following formula:
a = (v - u)/t
Where;
- a = acceleration (m/s²)
- v = final velocity (m/s)
- u = initial velocity (m/s)
- t = time (s)
According to this question, a car starts at 12.5 m/s and reaches 25.5 m/s in 5.00 seconds.
a = (25.5 - 12.5)/5
a = 13.0/5
a = 2.6m/s²
Therefore, the acceleration of a car that starts at 12.5 m/s and reaches 25.5 m/s in 5.00 seconds is 2.6m/s².
Learn more about acceleration at: brainly.com/question/12550364
#SPJ1
Answer:B
Explanation:
Given
speed of car 
mass of clump 
Radius of car tire 
Since the tire is rotating about axle so a centripetal force is acting constantly on each particle towards the center of tire.
Centripetal force is given by

where 



(inward)
Explanation:
that the people closer too the head of the table will feel more vibrations than the people at the end of the table. since the vibrations will slow down as they travel farther down the table
Hope this helps!!
Answer:
The frictional force acting on the bear during the slide is 207.5 N
Explanation:
Given;
mass of beam, m = 25-kg
vertical height, h = 12 m
speed of fall, v = 6 m/s
Change in potential energy of the beam:
ΔP.E = -mgh = - 25 x 9.8 x 12 = -2940 J
Change in kinetic energy of the beam:
Δ K.E = ¹/₂mv² = ¹/₂ x 25 x (6)² = 450 J
Change in thermal energy of the system due to friction:
ΔE = - (ΔP.E + Δ K.E)
ΔE = - (-2940 J + 450 J)
ΔE = 2940 J - 450 J = 2490 J
Frictional force (in N) acting on the bear during the slide:
F x d = Fk x h = ΔE
Where;
Fk is the frictional force
Fk = ΔE/h
Fk = 2490J / 12m
Fk = 207.5 N
Therefore, the frictional force acting on the bear during the slide is 207.5 N
Answer:
light waves can be converted to electricity through <em>a solar cell</em>
Explanation: