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2 years ago

What is the acceleration of an 24 kg object that applies a force of 130N?

Physics

1 answer:

WITCHER [35]2 years ago

6 0

Answer:

To find the acceleration of the object we have to apply Newton second law of motion that is F = mass × acceleration.

Explanation:

Given ,

F = 130N

M = 24kg

A = ?

F = m× a

then ,

130N = 24kg ×a

a = 130/24 = 5 m/s.

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The statement that no two electrons in the same atom can have the same four quantum numbers is a restatement of

andreev551 [17]

Answer:

Pauli exclusion principle

Explanation:

Pauli's exclusion principle speaks to the quantum numbers assigned to an electron to describe it's general position and movement. Two electrons can occupy the same energy level (which is described by the first quantum number-the principal quantum number), the orbital angular momentum quantum number (represented by the second number) and magnetic quantum number. electrons that have the same value for all three numbers will have different spins. one will have positive a half while the other has negative a half. Therefore they will never have the same complement of quantum numbers

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3 years ago

If a display has a dynamic range of 20 dB and the smallest voltage it can handle is 200 mV, then the largest voltage it can hand

DedPeter [7]

Answer:

The largest voltage is 0.02 V.

(d) is correct option.

Explanation:

Given that,

Range = 20 dB

Smallest voltage = 200 mV

We need to calculate the largest voltage

Using formula of voltage gain

$G_{dB}=10 log_{10}(\dfrac{V_{out}^2}{V_{in}^{2}})$

$20 =10 log_{10}(\dfrac{V_{out}^2}{V_{in}^{2}})$

$2=log_{10}(\dfrac{V_{out}^2}{V_{in}^{2}})$

$10^2=\dfrac{V_{out}^2}{V_{in}^{2}}$

$\dfrac{V_{out}}{V_{in}^}=10$

$V_{in}=\dfrac{V_{out}}{10}$

$V_{in}=\dfrac{200}{10}$

$V_{in}=20\ mV$

$V_{in}=0.02\ V$

Hence, The largest voltage is 0.02 V.

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3 years ago

A sealed cubical container 10.0 cm on a side contains three times Avogadro's number of molecules at a temperature of 24.0°C. Fin

rodikova [14]

This question involves the concepts of general gas equation and pressure.

The force exerted by the gas on one of the walls of the container is "74.08 KN".

First, we will use the general gas equation to find out the pressure of the gas:

$PV = nRT$

where,

P = Pressure of the gas = ?

V = Volume of cube = (side length)³ = (10 cm)³ = (0.1 m)³ = 0.001 m³

n = no. of moles = 3 (since molecules equal to avogadro's number make up 1 mole)

R = general gas constant = 8.314 J/mol.K

T = Absolute Temperature = 24°C + 273 = 297 K

Therefore,

$P = \frac{(3)(8.314\ J/mol.k)(297\ K)}{0.001\ m^3}$

P = 7407.78 KPa

Now, the force on one wall can be given as follows:

$P =\frac{F}{A}\\\\F=PA$

where,

A = area of one wall = (side length)² = (0.1 m)² = 0.01 m²

Therefore,

$F=(7407.78\ KPa)(0.01\ m^2)\\$

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Learn more about the general gas equation here:

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3 years ago

At a certain time a particle had a speed of 17 m/s in the positive x direction, and 3.0 s later its speed was 28 m/s in the oppo

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Answer:

i wanna say 11 forgive me if wrong.

Explanation:

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3 years ago

The blades of a metal cutter are shorter than the blades of paper cutter scissor. Give reason

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Answer:

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3 years ago