Answer:
6.6 atm
Explanation:
Using the general gas law
P₁V₁/T₁ = P₂V₂/T₂
Let P₂ be the new pressure
So, P₂ = P₁V₁T₂/V₂T₁
Since V₂ = 2V₁ , P₁ = 12 atm and T₁ = 273 + t where t = temperature in Celsius
T₂ = 273 + 2t (since its Celsius temperature doubles).
Substituting these values into the equation for P₂, we have
P₂ = P₁V₁(273 + 2t)/2V₁(273 + t)
P₂ = 12(273 + 2t)/[2(273 + t)]
P₂ = 6(273 + 2t)/(273 + t)]
assume t = 30 °C on a comfortable spring day
P₂ = 6(273 + 2(30))/(273 + 30)]
P₂ = 6(273 + 60))/(273 + 30)]
P₂ = 6(333))/(303)]
P₂ = 6.6 atm
Answer:
5.74s
Explanation:
We can first solve for the initial angular velocity using the following formula
Where is the final angular velocity, is the angular acceleration and is the angular displacement
So for the wheel to get from 22.4 to -22.4 with angular acceleration of -7.8 then the time it takes must be
Answer:
So the car would skid 4 times the initial skidding displacement under the identical conditions when the car's initial velocity is just double.
Explanation:
Under identical conditions when the brakes are applied for the same body moving with twice the initial speed then we can analyse using the equation of motion.
Initially:
...........................(1)
where:
final velocity of the car = 0 (because the car stops)
initial velocity of the car
acceleration of the car (here it is deceleration and hence taken with negative sign)
displacement of the car before stopping
Final condition:
Initial velocity is,
So,
.............................(2)
Now divide eq. (2) by (1)
So the car would skid 4 times the initial skidding displacement under the identical conditions when the car's initial velocity is just double.