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ira [324]
3 years ago
7

The field lines around one end of a bar magnet are shown

Physics
2 answers:
Vitek1552 [10]3 years ago
8 0
<h3>C ⇒ IT IS A SOUTH POLE BECAUSE THE FIELD LINES ENTER THE MAGNET AT THIS END</h3>

In a magnet, the lines (forces) always enter through the <em>south </em>pole and leave through the <em>north</em> pole.

I hope that helps ya'll.

- sincerelynini

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>
Vlad1618 [11]3 years ago
7 0

Answer:

Explanation:

Field lines are lines of forces around a bar magnet. The show the direction of force field in a magnet.

Usually, around a bar magnet, the field lines originates and spreads out from the north pole.

Then they converge and enter through the south pole.

Therefore, we can make our choice by inspecting the given diagram. If the lines enters through the pole, it is the south pole.

Where they originate or leave is the north pole.

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PLEASE HELP!!! WILL GIVE 30 POINTS!! HAS TO BE CORRECT!
belka [17]

Answer:

Disruption to electricity power grid

Explanation:

We're looking a a solar flare. This will whip solar particles at high velocity into space and, If they are near earth, will interact with the earth's magnetic field. These magnetic changes will be measurable in the electric grid. Whether they are strong enough to cause "disruption" depends on a huge number of factors such as strength of and angles of the interacting magnetic fields and location of grid infrastructure,

4 0
2 years ago
Read 2 more answers
Without sea otters, sea urchins would overgraze on kelp beds, dramatically changing the marine community. true/false
Bumek [7]
True is the anwser to your question
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5 0
3 years ago
Read 2 more answers
A 60kg bicyclist (including the bicycle) is pedaling to the
Fittoniya [83]

a) 4 forces

b) 186 N

c) 246 N

Explanation:

a)

Let's count the forces acting on the bicylist:

1) Weight (W=mg): this is the gravitational force exerted on the bicyclist by the Earth, which pulls the bicyclist towards the Earth's centre; so, this force acts downward (m = mass of the bicyclist, g = acceleration due to gravity)

2) Normal reaction (N): this is the reaction force exerted by the road on the bicyclist. This force acts vertically upward, and it balances the weight, so its magnitude is equal to the weight of the bicyclist, and its direction is opposite

3) Applied force (F_A): this is the force exerted by the bicylicist to push the bike forward. Its direction is forward

4) Air drag (R): this is the force exerted by the air on the bicyclist and resisting the motion of the bike; its direction is opposite to the motion of the bike, so it is in the backward direction

So, we have 4 forces in total.

b)

Here we can find the net force on the bicyclist by using Newton's second law of motion, which states that the net force acting on a body is equal to the product between the mass of the body and its acceleration:

F_{net}=ma

where

F_{net} is the net force

m is the mass of the body

a is its acceleration

In this problem we have:

m = 60 kg is the mass of the bicyclist

a=3.1 m/s^2 is its acceleration

Substituting, we find the net force on the bicyclist:

F_{net}=(60)(3.1)=186 N

c)

We can write the net force acting on the bicyclist in the horizontal direction as the resultant of the two forces acting along this direction, so:

F_{net}=F_a-R

where:

F_{net} is the net force

F_a is the applied force (forward)

R is the air drag (backward)

In this problem we have:

F_{net}=186 N is the net force (found in part b)

R=60 N is the magnitude of the air drag

Solving for F_a, we find the force produced by the bicyclist while pedaling:

F_a=F_{net}+R=186+60=246 N

3 0
3 years ago
A 103 kg physics professor has fallen into the Grand Canyon. Luckily, he managed to grab a branch and is now hanging 93 m below
siniylev [52]

Answer:

125.83672 seconds

Explanation:

P = Power of the horse = 1 hp = 746 W (as it is not given we have assumed the horse has the power of 1 hp)

m = Mass of professor = 103 kg

g = Acceleration due to gravity = 9.8 m/s²

h = Height of professor = 93 m

Work done would be equal to the potential energy

W=mgh\\\Rightarrow W=103\times 9.8\times 93\\\Rightarrow W=93874.2\ J

Power is given by

P=\frac{W}{t}\\\Rightarrow t=\frac{W}{P}\\\Rightarrow t=\frac{93874.2}{746}\\\Rightarrow t=125.83672\ seconds

The time taken by the horse to pull the professor is 125.83672 seconds

6 0
3 years ago
When the medium is uniform, how do light waves pass through it?
LekaFEV [45]

The correct answer is, A) Straight line motion

I took the quiz

8 0
3 years ago
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