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4 years ago

An object is in motion when it undergoes a continuous change of what?

1 answer:

5 0

Answer:
continuous change in position with respect to time

Explanation:
Velocity is defined as the rate of change of the position of an object with respect to its time.
It's the vector quantity of speed as it has both magnitude and direction.

Hope this helps :)

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On the moon, a feather is dropped from a height of 1.40 m. The acceleration of gravity on the moon is -1.67 m/s2. Determine the

Molodets [167]

Answer:

1.29 s

Explanation:

Height = 1.40m
Acclⁿ due to gravity = 1.67 m/s²
Time of descent = ?

As we know that ,

$\sf\longrightarrow Time_{descent}= \sqrt{\dfrac{2H}{g_{(moon)}}}\\\\\sf\longrightarrow t_d = \sqrt{\dfrac{ 2\times 1.4}{1.67}} \\\\\sf\longrightarrow t_d =\sqrt{1.67} s\\\\\sf\longrightarrow \boxed{\red{\sf Time_{descent}= 1.29 s }}$

4 0

3 years ago

Is kane brown a true country singer?<br> A.yes<br> B.no

Kryger [21]

Answer: hes not a country singer if thats what your asking

Explanation:

6 0

3 years ago

Read 2 more answers

Suppose you design an apparatus in which a uniformly charged disk of radius R is to produce an electric field. The field magnitu

ANEK [815]

Answer:

The electric field will be decreased by 29%

Explanation:

The distance between point P from the distance z = 2.0 R

Inner radius = R/2

Outer raidus = R

Thus;

The electrical field due to disk is:

$\hat {K_a} = \dfrac{\sigma}{2 \varepsilon _o} \Big( 1 - \dfrac{z}{\sqrt{z^2+R_i^2}} \Big)$ )

$\implies \dfrac{\sigma}{2 \vaepsilon _o} \Big ( 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0\ R)^2+(R)^2}} \Big)$

Similarly;

$\hat {K_b} = \hat {k_a} - \dfrac{\sigma}{2 \varepsilon_o} \Big( 1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ r)^2 + (\dfrac{R}{2}^2)}}\Big)$

However; the relative difference is: $\dfrac{\hat {k_a} - \hat {k_b}}{\hat {k_a} }= \dfrac{E_a -E_a + \dfrac{\sigma}{2 \varepsilon_o \Big[1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ R)^2 + (\dfrac{R}{2})^2}} \Big] } } { \dfrac{\sigma}{2 \varepsilon_o \Big [ 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0 \ R)^2 + (R)^2}} \Big] }}$

$\dfrac{\hat {k_a} - \hat {k_b}}{\hat {k_a} }= \dfrac{1 - \dfrac{2.0}{\sqrt{(2.0)^2 + \dfrac{1}{4}}} }{1 - \dfrac{2.0 }{\sqrt{(2.0)^2 + 1}}}$

$= 0.2828 \\ \\ \mathbf{\simeq 29\%}$

3 0

3 years ago

Challenge Problem (Extra Credit) A car with bad shocks has a mass of 1500 kg. Before you go for a drive with three of your frien

Nastasia [14]

Answer:

167.354 m

Explanation:

We are given;

The mass of the car with bad shock;

m = 1500 kg

The distance at which the car sinks; x =

6 cm = 6 × 10^(−2) m

The total mass of 4 people; m_t = 11 kg

The total speed in the highway; V = 65

mph = 29.058 m/s

The spring's constant can be calculated from the formula;

F = Kx

F is also equal to mg.

Thus;

m_t × g = Kx

K = (m_t × g)/x

K = (11 × 9.81)/(6 × 10^(−2))

K = 1798.5 N/m

Mass of car and four people;m_(c+t) = 1500 + 11 = 1511 kg

Thus, the period cam be calculated from the formula;

T = 2π√((m_c+t)/k)

T = 2π√(1511/1798.5)

T = 5.759 s

the distance between adjacent bumps is calculated from;

Velocity = distance/time

Distance = velocity x time

Distance = 29.058 × 5.759

Distance = 167.354 m

4 0

4 years ago

A car is moving at a initial velocity of 20 meters per second accelerates at a rate of 1.5 meters per second squared for 4 secon

Brrunno [24]

Answered using calculus.
Antidifferentiated the acceleration to get velocity. Added variable c as we do not know if there was an extra number there yet.
Knowing that when time is 0, the velocity is 20, we can substitute those numbers into the equation and find that c = 20.
Now we have full velocity equation: v = 1.5t + 20
Now we substitute 4 into t to find out the velocity after 4 seconds. This gives us the final answer of 26m/s

5 0

4 years ago