Question

How much water, in grams, can be made from

Answer 1

Answer:

$m_{H_2O}=73.0gH_2O$

Explanation:

Hello there!

In this case, since the formation of water from hydrogen and oxygen is:

$2H_2+O_2\rightarrow 2H_2O$

Whereas we find a 2:2 mole ratio of hydrogen to water. In such a way, by using the Avogadro's number, the aforementioned mole ratio and the molar mass of water (18.02 g/mol), we obtain the following grams of water product:

$m_{H_2O}=2.44x10^{24}molec*\frac{1molH_2}{6.022x10^{23}molec}*\frac{2molH_2O}{2molH_2}*\frac{18.02gH_2O}{1molH_2O}\\\\ m_{H_2O}=73.0gH_2O$

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