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Alinara [238K]
3 years ago
12

Describing a Physical Change

Physics
1 answer:
babymother [125]3 years ago
6 0

Answer:

physical change is the temporary change or riversible change here the physical properties r only changed

for example when water is cooled its get freezed Nd becomes ice similarly wen ice is heated again then it becomes water so here it's not changed permanently

I hope my ans is comprehensive

plz add me in brainliest Nd plz plz plz follow me I request u

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As a woman walks, her entire weight is momentarily placed on one heel of her high-heeled shoes. Calculate the pressure exerted o
astraxan [27]

Answer:

3.6 x 10⁶ Pa

Explanation:

A = Area of the heel = 1.50 cm² = 1.50 x 10⁻⁴ m²

m = mass of the woman = 55.0 kg

g = acceleration due to gravity = 9.8 m/s²

Force of gravity on the heel is given as

F = mg

Inserting the values

F = (55) (9.8)

F = 539 N

Pressure exerted on the floor is given as

P = \frac{F}{A}

P = \frac{539}{1.5\times 10^{-4}}

P = 3.6 x 10⁶ Pa

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3 years ago
Sound waves are mechanical waves in which the particles in the medium vibrate in a direction parallel to the direction of energy
ch4aika [34]

C longitudnal waves

4 0
3 years ago
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When a carousel is in motion, the movement of the carousel horse can best be described as?
tatiyna
Supposing the carousel is rotating with constant speed, the movement is uniform angular motion.
5 0
3 years ago
A 0.20-kg mass is oscillating on a spring over a horizontal frictionless surface. When it is at a displacement of 2.6 cm for equ
valentinak56 [21]

Explanation:

The given data is as follows.

                    mass = 0.20 kg

              displacement = 2.6 cm

              Kinetic energy = 1.4 J

       Spring potential energy = 2.2 J

Now, we will calculate the total energy present present as follows.

         Total energy = Kinetic energy + spring potential energy

                           = 1.4 J + 2.2 J

                            = 3.6 Joules

As maximum kinetic energy of the object will be equal to the total energy.

So,      K.E = Total energy

                = 3.6 J

Also, we know that

                  K.E = \frac{1}{2}mv^{2}_{m}

or,                   v = \sqrt{\frac{2K.E}{m}}

                        = \sqrt{2 \times 3.6 J}{0.2 kg}

                        = \sqrt{36}

                        = 6 m/s

thus, we can conclude that maximum speed of the mass during its oscillation is 6 m/s.

4 0
3 years ago
Answer it or not your choice
Zigmanuir [339]

Answer:

Explanation:

(a) 0 to 90

(b) 90 to 180

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