Answer:1. 1.0 1.0 1.4
Step-by-step explanation:
Answer:
Volume of rectangular prism = 175 / 6 inch³
Step-by-step explanation:
Given:
Base area of rectangular prism = 23 ¹/₃ inch² = 70 / 3 inch²
Height of rectangular prism = 1 ¹/₄ inch = 5 / 4 inch
Find:
Volume of rectangular prism
Computation:
Volume of rectangular prism = Base area of rectangular prism x Height of rectangular prism
Volume of rectangular prism = [70 / 3] x [5 / 4]
Volume of rectangular prism = [350 / 12]
Volume of rectangular prism = 175 / 6 inch³
Answer:
(4/3, 7/3)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
- Terms/Coefficients
- Coordinates (x, y)
- Solving systems of equations of using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
7x - y = 7
x + 2y = 6
<u>Step 2: Rewrite Systems</u>
Equation: x + 2y = 6
- [Subtraction Property of Equality] Subtract 2y on both sides: x = 6 - 2y
<u>Step 3: Redefine Systems</u>
7x - y = 7
x = 6 - 2y
<u>Step 4: Solve for </u><em><u>y</u></em>
<em>Substitution</em>
- Substitute in <em>x</em>: 7(6 - 2y) - y = 7
- Distribute 7: 42 - 14y - y = 7
- Combine like terms: 42 - 15y = 7
- [Subtraction Property of Equality] Subtract 42 on both sides: -15y = -35
- [Division Property of Equality] Divide -15 on both sides: y = 7/3
<u>Step 5: Solve for </u><em><u>x</u></em>
- Define original equation: x + 2y = 6
- Substitute in <em>y</em>: x + 2(7/3) = 6
- Multiply: x + 14/3 = 6
- [Subtraction Property of Equality] Subtract 14/3 on both sides: x = 4/3
Answer:
3/32 in^3
Step-by-step explanation:
volume = length * width * height
V=3/4 * 1/2 * 1/4
V= 3/32
If
and
, separate variables in the differential equation to get

Integrate both sides:

Use the initial condition to solve for
:

Then the particular solution to the initial value problem is

(A)