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svp [43]
2 years ago
5

Write as logarithm with base 4: 4 -5 2 -4

Mathematics
1 answer:
NeX [460]2 years ago
8 0

Answer:

log_4(256)=4

log_4(1/1024)=-5

log_4(16)=2

log_4(1/256)=-4

Step-by-step explanation:

We want to write a number, x, such that

Log_4(y)=x.

In exponential form that is 4^x=y.

So first number is x=4.

4^4=256 which means log_4(256) is 4 as a logarithm with base 4.

The second number is x=-5.

4^-5=1/4^5=1/1024 which means log_4(1/1024) is -5 as a logarithm with base 4.

The third number is x=2.

4^2=16 so log_4(16) is 2 as a logarithm with base 4.

The fourth number is x=-4.

Since 4^4=256 then 4^-4=1/256 which means -4 as a logarithm with base 4 is log_4(1/256).

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<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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  2. Parenthesis
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  4. Multiplication
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Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
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<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define Systems</u>

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<u>Step 2: Rewrite Systems</u>

Equation: x + 2y = 6

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<u>Step 3: Redefine Systems</u>

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<u>Step 4: Solve for </u><em><u>y</u></em>

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  1. Substitute in <em>x</em>:                                                                                                7(6 - 2y) - y = 7
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  3. Combine like terms:                                                                                       42 - 15y = 7
  4. [Subtraction Property of Equality] Subtract 42 on both sides:                    -15y = -35
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<u>Step 5: Solve for </u><em><u>x</u></em>

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  4. [Subtraction Property of Equality] Subtract 14/3 on both sides:                  x = 4/3
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