Asthenosphere.
This layer is the only one of the choices located inside of the Earth and is around the lithosphere and the mesosphere.
Answer :
The substance is in the gas phase only in region → 5
The substance is in both the liquid and the solid phase in region → 2
The substance is in only the liquid phase in region → 3
The melting point is the temperature at region → 2
The boiling point is the temperature at region → 4
Explanation :
Six phases of substance:
- Melting or fusion : In this process the phase changes from solid state to liquid state at constant temperature.
- Freezing : In this process the phase changes from liquid state to solid state at constant temperature.
- Evaporation : In this process the phase changes from liquid state to gaseous state at constant temperature.
- Condensation : In this process the phase changes from gaseous state to liquid state at constant temperature.
- Sublimation : In this process the phase changes from solid state to gaseous state without passing through the liquid state at constant temperature.
- Deposition : In this process the phase changes from gaseous state to solid state without passing through the liquid state at constant temperature.
the branch of science that deals with the identification of the substances of which matter is composed
Answer:
The length of the cubical container will be 17.206 m.
Explanation:
Amount of carbon dioxide gas generated in year by person = 10,000 kg
1 kg = 1000 g
10,000 kg = 10,000 × 1000 g = 10,000,000 g
Moles of carbon dioxide =
Volume of carbon dioxide gas at STP= V
STP conditions = P = 1 atm , T = 273 K
Using Ideal gas equation ;
Let the side of the cube = a
Volume of the cube =
The length of the cubical container will be 17.206 m.
Answer:
3.8 M
Explanation:
Volume of acid used VA= 57.0 - 37.5 = 19.5 ml
Volume of base used VB= 67.8 - 45.0 = 22.8 ml
Equation of the reaction
2HNO3(aq) + Ca(OH)2(aq) --------> Ca(NO3)2(aq) + 2H2O(l)
Number of moles of acid NA= 2
Number of moles of base NB= 1
Concentration of acid CA= ???
Concentration of base CB= 1.63 M
CAVA/CBVB = NA/NB
CAVANB = CBVBNA
CA= CBVBNA/VANB
CA= 1.63 × 22.8 × 2/ 19.5 × 1
CA= 3.8 M
HENCE THE MOLARITY OF THE ACID IS 3.8 M.