Answer:
45.8 mL
Explanation:
If all variables are held constant, the new volume can be found using the Boyle's Law equation. The equation looks like this:
P₁V₁ = P₂V₂
In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new volume by plugging the given values into the equation and simplifying.
P₁ = 3.1 atm P₂ = 10.5 atm
V₁ = 155 mL V₂ = ? mL
P₁V₁ = P₂V₂ <----- Boyle's Law equation
(3.1 atm)(155 mL) = (10.5 atm)V₂ <----- Insert values
480.5 = (10.5 atm)V₂ <----- Multiply 3.1 and 155
45.8 = V₂ <----- Divide both sides by 10.5
Answer:
An emerald can be described as a pure substance because it is a compound. it's a pure substance because it is an element. It's an impure substance because it is chemically combined, an impure substance because it is a mixture.
Explanation:
Answer:
A liquid is a nearly incompressible fluid that conforms to the shape of its container but retains a (nearly) constant volume independent of pressure. As such, it is one of the four fundamental states of matter (the others being solid, gas, and plasma), and is the only state with a definite volume but no fixed shape.
Answer:Consider a sample that is a mixture composed of biphenyl, benzoic acid, and benzyl alcohol. The sample is spotted on a TLC ... Predict the relative Rf values for the three components in the sample. Hint: See Table 19.3. ... The sample is spotted on a TLC plate and developed in solvent mixture. We are going to predict the ...
Explanation:MORE POWER
1) <span>flows of hot plasma in the convection zone
2) dark spots that appear sometimes because of </span><span>concentrations of magnetic field flux
3) "</span><span>a brief eruption of intense high-energy radiation from the sun's surface"
4) gas extended out from the corona but is attached to the sun and can reach great distances
5) large area in cocrona which is less dense and has cooler temperature they occur when "</span><span>the Sun's magnetic field is open to interplanetary space"</span>
