Answer:
2.90 x 10⁻¹¹moldm⁻³
Explanation:
Given parameters:
[H⁺] = 3.5 x 10⁻⁴mol/dm³
Unknown
[OH⁻] = ?
Solution;
The ionic product of water can be used to solve this problem. It has been experimentally determined to be 1 x 10⁻¹⁴mol² dm⁻⁶
[H⁺] [OH⁻] = 1 x 10⁻¹⁴
Therefore;
[OH⁻] = 
= 
= 0.29 x 10⁻¹⁰moldm⁻³
= 2.90 x 10⁻¹¹moldm⁻³
Explanation:
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Answer:
56.47%
Explanation:
In this question, we are given;
- Theoretical yield of sulfur dioxide as 680 g
- Actual yield of sulfur dioxide as 384 g
We are required to calculate the percent yield for the reaction;
- We need to know how percent yield is calculated;
- % yield = (Actual yield ÷ Theoretical yield) × 100%
Therefore;
In this case;
% yield = (384 g ÷ 680 g) × 100%
= 56.47%
Thus, the percent yield for the reaction is 56.47%
Answer:
15 mL
Explanation:
El valor de concentración de 4% v/v nos dice que de cada 100 mL de cerveza, 4 mL son de alcohol.
Con eso en mente podemos <u>calcular los mL de alcohol presentes en 375 mL</u>, de la siguiente forma:
En 375 mL de cerveza de concentración 4% v/v, hay 15 mL de alcohol.
Answer:
Do Nothing
Explanation:
Charges are transferred by friction when two different types of bodies are rubbed together. This is known as charging by friction.
However, when two materials of the same type are rubbed together, no charge is transferred from one object to the other hence there is no transfer of charges by friction and none of the two glass rods are charged.
Therefore, when one of the glass rods is brought close but does not touch the pith ball, nothing happens.
