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weeeeeb [17]
3 years ago
6

I just need to know which ones are insulators and the others conductors

Chemistry
1 answer:
Lera25 [3.4K]3 years ago
5 0

Answer:

below

Explanation:

Insulators: wood, tire, glass cup, wool hat

Conductors: frying pan, penny, wire

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Can we cover the earth with one mole of pennies?
lara [203]

Answer:

\no

Explanation:

6 0
3 years ago
Complete combustion of a 0.600-g sample of a compound in a bomb calorimeter releases 24.0 kJ of heat. The bomb calorimeter has a
coldgirl [10]

The final temperature, t₂ = 30.9 °C

<h3>Further explanation</h3>

Given

24.0 kJ of heat = 24,000 J

Mass of calorimeter = 1.3 kg = 1300 g

Cs = 3.41 J/g°C

t₁= 25.5 °C

Required

The final temperature, t₂

Solution

Q = m.Cs.Δt

Q out (combustion of compound) = Q in (calorimeter)

24,000 = 1300 x 3.41 x (t₂-25.5)

t₂ = 30.9 °C

3 0
3 years ago
Read 2 more answers
Neon (Ne) is in group 18. This element
Aleonysh [2.5K]

Answer:

option 3

Explanation:

Neon is one of the noble gases. Noble gases don't react with any element because of their stability. Elements of Group 18 in Periodic Table are inert gases.

8 0
4 years ago
Compare the density of the ocean crust and the continental crust. If they were to collide, predict which one would push under th
uysha [10]

Answer:

The difference between the density of the ocean crust and the continental crust is the fact that the ocean crust is denser than the continental crust. Meaning, the continental crust is likely to push over the oceanic crust considering it has less dense.

Explanation:

I hope this helps, the last time I learned this was in 5th grade and I am i currently in the 11th grade....

5 0
3 years ago
How many molecules of ethane are present in 64.28 liters of ethane gas (C2H6) at STP
Rom4ik [11]

Answer : The molecule of ethane present in 64.28 L of ethane gas at STP is, 17.277\times 10^{23} molecule.

Solution :

At STP,

22.4 L volume of ethane present in 1 mole of ethane gas

64.28 L volume of ethane present in \frac{64.28L}{22.4L}\times 1mole=2.869moles of ethane gas

And, as we know that

1 mole of ethane molecule contains 6.022\times 10^{23} molecules of ethane

2.869 moles of ethane molecule contains 2.869\times 6.022\times 10^{23}=17.277\times 10^{23} molecules of ethane

Therefore, the molecule of ethane present in 64.28 L of ethane gas at STP is, 17.277\times 10^{23} molecule.

4 0
3 years ago
Read 2 more answers
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