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weeeeeb [17]
3 years ago
6

I just need to know which ones are insulators and the others conductors

Chemistry
1 answer:
Lera25 [3.4K]3 years ago
5 0

Answer:

below

Explanation:

Insulators: wood, tire, glass cup, wool hat

Conductors: frying pan, penny, wire

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If an isotope of an element has 33 neutrons and a mass number of 64, how many electrons must it have?
larisa [96]
The mass number is the sum of the protons and neutrons
64 = #protons + #neutrons
Find the number of protons given the number of neutrons
64 = #protons + 33
#protons = 31
In a neutral element (such as this), the number of electrons equals the number of protons
#electrons = #protons
#electrons = 31
7 0
3 years ago
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Why is O2 necessary for rusting?
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O2 isn't necessary for rusting, but some source of oxygen is required. Rust is just another name for iron oxide, and without oxygen there can't be oxide.

Hope this helps,

Davinia.

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Fill in the blanks to describe the work of Ben Kennedy, a volcanologist who works in New Zealand. To learn more about why his pu
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What happened to the FREQUENCY of the wave as the instrument got bigger?
Archy [21]

Answer:

The wavelengths at which resonance occurs are proportional to the length of the instrument, so you can play different notes by changing the length. In general the larger the instrument the longer the wavelength of the fundamental and the lower the frequency range of the instrument.

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4 0
3 years ago
When a 2.00 g sample of KCl is dissolved in water in a calorimeter that has a total heat capacity of 1.28 kJ ⋅ K − 1 , the tempe
Alchen [17]

Answer : The molar heat of solution of KCl is, 17.19 kJ/mol

Explanation :

First we have to calculate the heat of solution.

q=c\times (\Delta T)

where,

q = heat produced = ?

c = specific heat capacity of water = 1.28kJ/K

\Delta T = change in temperature = 0.360 K

Now put all the given values in the above formula, we get:

q=1.28kJ/K\times 0.360K

q=0.4608kJ=460.8J

Now we have to calculate the molar heat solution of KCl.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy change = ?

q = heat released = 460.8 J

m = mass of KCl = 2.00 g

Molar mass of KCl = 74.55 g/mol

\text{Moles of }KCl=\frac{\text{Mass of }KCl}{\text{Molar mass of }KCl}=\frac{2.00g}{74.55g/mole}=0.0268mole

Now put all the given values in the above formula, we get:

\Delta H=\frac{460.8J}{0.0268mole}

\Delta H=17194.029J/mol=17.19kJ/mol

Therefore, the molar heat of solution of KCl is, 17.19 kJ/mol

7 0
3 years ago
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