Li2CO3 + Ca3(PO4)2 = Li3PO4 + CaCO3
The answer for this would be 69.6
Answer:
c) .51835
Explanation:
Let the relative abundance of the lighter of the two isotopes be X we have
Then the relative abundance of the heavier isotope is then (1-X)
Whereby we have that in nature the amount of the lighter silver found in proportion is X and the heavier isotope of silver is present as (1-X) proportion in nature.
To calculate the relative atomic mass of silver, we have
(Mass of light weight silver)×X + (mass of heavier isotope of silver×(1-X) = relative atomic mass of silver
106.90509(X) + 108.9047(1-X)
108.9-108.9(x)+106.9(x) = 107.87
-2x-1.03 = 0.517450902926
Closest answer is c
c) .5184
The relative atomic mass of isotopes is the weighted average by the mole-fraction of abundance of these isotopes which gives the atomic weight that is listed for that element on the periodic table.
Answer:
9.62moles of NH₃
Explanation:
Given parameters:
Number of moles of nitrogen = 4.81moles
Unknown:
Number of moles of NH₃ = ?
Solution:
To solve this problem, we need to establish a balanced reaction equation:
N₂ + 3H₂ → 2NH₃
Now, we can solve the problem by working from the known to the unknown.
1 mole of N₂ produced 2 moles of NH₃
4.81moles of N₂ will produce 2 x 4.81 = 9.62moles of NH₃
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