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Tju [1.3M]
3 years ago
13

The mass of the parts is always ___ the mass of the whole when looking at nuclear masses.

Physics
1 answer:
Allushta [10]3 years ago
6 0
<span>When looking at nuclear masses we speak of the processes nuclear fision and nuclear fusion. </span>In fission a nucleus breaks up, into two nuclei. In fusion on the other hand two light nuclei combine to form one heavier nucleus. The relation 
E=m*c^2. explains the difference in masses. <span>
So, in case of nuclear fusion t</span><span>he mass of the parts is always </span>more than the mass of the whole when looking at nuclear masses. In case of nuclear fusion. And in case of nuclear fision, the mass of the parts is always less<span> than the mass of the whole when looking at nuclear masses. In case of nuclear fusion</span>
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Someone pls help with only if you know correct answer!???
Roman55 [17]

Answer:

A 2.0 kg ball, A, is moving with a velocity of 5.00 m/s due west. It collides with a stationary ball, B, also with a mass of 2.0 kg. After the collision

Explanation:

5 0
3 years ago
Read 2 more answers
Sound travels through air at 343 m/s,
sasho [114]

The sound wave will have traveled 2565 m  farther in water than in air.

Answer:

Explanation:

It is known that distance covered by any object is directly proportional to the velocity of the object and the time taken to cover that distance.

Distance = Velocity × Time.

So if time is kept constant, then the distance covered by a wave can vary depending on the velocity of the wave.

As we can see in the present case, the velocity of sound wave in air is 343 m/s. So in 2.25 s, the sound wave will be able to cover the distance as shown below.

Distance = 343 × 2.25 =771.75 m

And for the sound wave travelling in fresh water, the velocity is given as 1483 m/s. So in a time interval of 2.25 s, the distance can be determined as the product of velocity and time.

Distance = 1483×2.25=3337 m.

Since, the velocity of sound wave travelling in fresh water is greater than the sound wave travelling in air, the distance traveled by sound wave in fresh water will be greater.

Difference in distance covered in water and air = 3337-772 m = 2565 m

So the sound wave will have traveled 2565 m  farther in water than in air.

5 0
3 years ago
A scientific law is ____________________A. A rule enacted by the National Academy of Sciences. B. What scientists expect will al
lapo4ka [179]

Your question asks what a scientific law is.

Your answer would be B). What scientists expect will always happen under particular circumstances

A scientific law is something that will always happen, it is mostly like a repeat when doing a experiment with certain factors in place. This is also known as a "natural law" because something will naturally happen when it is enacted with the same factors for multiple "trials". This "scientific law" will allow scientist to predict what would happen during other multiple trials that are conducted. Concise data would be received from these trials.

An example of a scientific law is Newton's law of gravitation.

Therefore, your answer would be B.

5 0
3 years ago
4. A businesswoman on a trip flies a total of 23,000 km. The first day she traveled 4000 km, the second day 11,000 km, and on th
lutik1710 [3]

Answer:

14.035087719298246 ≈ 14 hours

Explanation:

just subtract the 4000 and the 11000 from 23000 which gives you 8000. And then divide that my 570

3 0
3 years ago
A 54 kg man holding a 0.65 kg ball stands on a frozen pond next to a wall. He throws the ball at the wall with a speed of 12.1 m
Inessa [10]

Answer:

The velocity of the man is 0.144 m/s

Explanation:

This is a case of conservation of momentum.

The momentum of the moving ball before it was caught must equal the momentum of the man and the ball after he catches the ball.

Mass of ball = 0.65 kg

Mass of the man = 54 kg

Velocity of the ball = 12.1 m/s

Before collision, momentum of the ball = mass x velocity

= 0.65 x 12.1 = 7.865 kg-m/s

After collision the momentum of the man and ball system is

(0.65 + 54)Vf = 54.65Vf

Where Vf is their final common velocity.

Equating the initial and final momentum,

7.865 = 54.65Vf

Vf = 7.865/54.65 = 0.144 m/s

4 0
3 years ago
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