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Temka [501]
4 years ago
5

A virtual image formed by convex lens is always

Physics
2 answers:
Dahasolnce [82]4 years ago
5 0

Answer is erect and magnified

natita [175]4 years ago
4 0

Answer:

2. erect and magnified

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Does a star's apparent brightness depend only on its distance from earth?
Arisa [49]
I dont think so. It also probably matters what type of str it is
4 0
3 years ago
Read 2 more answers
A horse pulls a wagon that weighs 10 times more than the horse. The horse pulls with a force of 500N to move the wagon forward.
____ [38]

Answer:

f. 500N

Explanation:

The force exerted by the wagon on the horse is 500N directed in the opposite path .

This is premised on the Newton's third law of motion which states that "action and reaction forces are equal and opposite in direction".

So, as the action force of 500N is used by the horse to drag the wagon, the wagon also exerts an oppositely directed force of 500N on the horse.

This way, the acceleration can continue.

5 0
4 years ago
A vertical spring with stiffness k originally is at rest with no mass attached. Then, a mass M is attached, and the spring rocks
Alina [70]

Answer:

The position of the spring in terms of g, m & k is x = \frac{m g}{k}

Explanation:

Stiffness of the spring = k

Mass = m

When a mass m is attached with the spring then spring stretched. in that case the force exerted on the spring is equal to weight of the mass attached.

⇒ Force exerted on the spring F = k x

⇒ m g = k x

⇒ x = \frac{m g}{k}

This is the position of the spring in terms of g, m & k.

8 0
4 years ago
Lunar missions have revealed that the moon has:
myrzilka [38]
That the moon has soil within its shadowy craters rich and useful material
5 0
3 years ago
A batter hits a foul ball. The 0.140-kg baseball that was approaching him at 40.0 m/s leaves the bat at 30.0 m/s in a direction
Korvikt [17]

Answer:

The magnitude of the impulse delivered to the baseball is 7.0 Ns

Explanation:

Given;

mass of the foul ball, m = 0.14 kg

initial velocity, u = 40 m/s

final velocity, v = 30 m/s in perpendicular direction

Impulse is given as change in momentum;

initial momentum in horizontal direction, Pi = mu

Pi = 0.14 x 40 = 5.6 Ns

final momentum in perpendicular direction, Pf = mv

Pf = 0.14 x 30

Pf = 4.2 Ns

The resultant impulse is given by;

J² = 5.6² + 4.2²

J² = 49

J = √49

J = 7.0 Ns

Therefore, the magnitude of the impulse delivered to the baseball is 7.0 Ns

5 0
3 years ago
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