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A virtual image formed by convex lens is always

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Dahasolnce [82]3 years ago

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Answer is erect and magnified

natita [175]3 years ago

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Answer:

2. erect and magnified

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Given that;

I₀ = 9.55 A

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a = 80.2 cm

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Replacing our values into above equation; we have:

$E_{rms} = \frac { {\frac{4 \pi*10^{-7}*0.325}{2 \pi} In (\frac{72.2+80.2}{80.2}) *9.55 (2 \pi *359)}}{\sqrt{2}}$

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Then the $P_{avg$ is calculated as:

$P_{avg} = \frac{E^2}{R}$

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