Problem 1, part (a)
<h3>Answer: False</h3>
For instance, 200 feet in real life can be reduced to scale down to say 2 inches on paper. So we have a reduction going on, and not an enlargement.
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Problem 1, part (b)
<h3>Answer: true</h3>
This is because a scale drawing involves similar polygons. This is true whenever any dilation is applied.
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Problem 2
I'm not sure how your teacher wanted you to answer this question. S/he didn't give you any numbers for the side lengths of the polygon. The angle measures are missing as well.
Answer:
It's hard to explain....
Step-by-step explanation:
Answer:
184 square cm
Step-by-step explanation:
The ratio of areas is the square of the ratio of the scale factor. The larger triangle has an area of ...
(15 cm²)(3.5²) = 183.75 cm²
The area of the similar triangle is about 184 cm².
Answer:
The upper limit of the 95% confidence interval is:
C.I_u = 200 + (58.8/
)
Step-by-step explanation:
The formula is given as:
C.I = μ ± Z*σ/![\sqrt{n}](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D)
The upper limit => C.I_u = μ + Z*σ/![\sqrt{n}](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D)
The lower limit => C.I_l = μ - Z*σ/![\sqrt{n}](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D)
The sample size (n) is not stated in the question. Hence, we calculate the upper limit with respect to n.
The upper limit => C.I_u = 200 + 1.96*(30/
)
= 200 + (1.96*30)/![\sqrt{n}](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D)
= 200 + 58.8/![\sqrt{n}](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D)