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Feliz [49]
3 years ago
7

A centripetal force of 210 N acts on a 1,600-kg satellite moving with a speed of 5,500 m/s in a circular orbit around a planet.

What is the radius of its orbit?
Physics
1 answer:
Dafna1 [17]3 years ago
4 0

Answer:

<h2>230476.19km</h2>

Explanation:

Step one:

given

Force F= 210N

mass m= 1600kg

velocity v=5500m/s

Step two

Required is the radius r

the expression for the force is

F_c = \frac{mv^2}{r}

substitute

210=1600*5500^2/r

cross multiply we have

210r=48400000000

divide both side by 210

r=230476190.476m

r=230476.19km

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Ezra is pulling a sled, filled with snow, by pulling on a rope attached to the sled. The rope makes an angle θ with respect to t
svetoff [14.1K]

Answer:

Explanation:

Given

rope makes an angle of \theta

Mass of sled and snow is m

Normal Force =F_N

applied Force is F

as Force is pulling in nature therefore normal reaction is given by

F_N=mg-F\sin \theta

Also F\cos \theta =f_r

f_r=\mu _k\cdot F_N

f_r=\mu _k\cdot (mg-F\sin \theta )

F\cos \theta =\mu _kF_N-------1

F\sin \theta =mg-F_N---------2

Squaring 1 & 2 and then adding

F^2=(\mu _kF_N)^2+(mg-F_N)^2

F=\sqrt{(\mu _kF_N)^2+(mg-F_N)^2}

Substitute value of F in 1

cos\theta =\frac{\mu _KF_N}{\sqrt{(\mu _kF_N)^2+(mg-F_N)^2}}

\theta =cos^{-1}(\frac{\mu _KF_N}{\sqrt{(\mu _kF_N)^2+(mg-F_N)^2}})

8 0
3 years ago
An upright spring with a 96g mass on it is compressed 2 cm. When
Alexeev081 [22]

Answer:

I only know answer A and it's 2825.28 N/m, with rounding it's 2825.5

Explanation:

Use the m*g*h=1/2*k*x^2 equation

96*9.81*60=1/2*k*2^2

5650.56=2k

5650.56/2=2825.28N/m

8 0
3 years ago
a train leaves a station heading east at 50 mph from that same station a car drives north at a speed of 30mph after 3 hours how
Alecsey [184]

Answer:

d = 175 miles

Explanation:

Train is moving towards East with constant speed of 50 mph

While car is moving at speed of 30 mph

so after t = 3 hours

the distance moved by the train is given as

d_1 = vt

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at the same time the distance moved by the car is given as

d_2 = 30(3) = 90 miles

now we know that both car and train is moving perpendicular to each other

So the distance between them after t = 3 hours is given as

d= \sqrt{d_1^2 + d_2^2}

d = \sqrt{150^2 + 90^2}

d = 175 miles

8 0
3 years ago
The difference between the Carbon 12 and Carbon 14 isotopes is the
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Answer:
The number of neutrons.

Explaination:
The atoms of carbon 12 contain 6 neutrons while the atoms of carbon 14 contain 8 neutrons
4 0
3 years ago
The three notches in the graph occur where the driver changed gears. Describe the changes in velocity and acceleration of the ca
kaheart [24]
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D ) the system would continue to move without any further, after and initial force has set in motion.

6 0
3 years ago
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