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3 years ago

Find a positive angle less than 360° that is coterminal with the given angle. 560

Mathematics

1 answer:

storchak [24]3 years ago

5 0

Answer:

200

Step-by-step explanation:

brainliest?

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Solve the system of equations:

Ahat [919]

Answer:

Step-by-step explanation:

z = 3

2y + z = 1

2y + 3 = 1 {substituting z =3}

2y = 1 -3

2y = -2

y = - 2/2

y = -1

2x +3y +2z = 13

2x + 3 * (-1) + 2*3 = 13 { {substituting z =3} and y = -1}

2x -3 + 6 =13

2x + 3 = 13

2x = 13 - 3

2x= 10

x = 10/2

x = 5

8 0

4 years ago

Choose the right answer which year had higher profit in month 3 ?

monitta

Answer:

Where is month 3 I will comment the answer if there is a graph or table to know!!! For house for economics. Sorry I don't understand...

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Dilate a triangle with vertices (0,0), (0,2) and (2,0) using the scale factor k=3. What is the value of the ratio (new to origin

seropon [69]

Answer:

Part a) The ratio of the perimeters is $3$

Part b) The ratio of the areas is $9$

Step-by-step explanation:

Part A) What is the value of the ratio (new to original) of the perimeters?

we know that

If two figures are similar, then the ratio of its perimeters is equal to the scale factor

Let

z-----> the scale factor

x-----> the perimeter of the new triangle

y-----> the perimeter of the original triangle

$z=\frac{x}{y}$

we have

$z=3$

substitute

$\frac{x}{y}=3$

Part B) What is the value of the ratio (new to original) of the areas?

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z-----> the scale factor

x-----> the area of the new triangle

y-----> the area of the original triangle

$z^{2}=\frac{x}{y}$

we have

$z=3$

substitute

$\frac{x}{y}=3^{2}$

$\frac{x}{y}=9}$

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=0%20%3D%20%20%20-%204.9t%20%7B%7D%5E%7B2%7D%20%20%2B%2027t%20%2B%202.4" id="TexFormula1" title

marta [7]

$0 = - 4.9t {}^{2} + 27t + 2.4$
Convert decimals to fractions

$0 = - \frac{49}{10} t {}^{2} + 27t + \frac{12}{5}$
Multiply both sides by 10

$0 = - 49t {}^{2} + 270t + 24$
Move expression to the left.

$0 + 49t {}^{2} - 270t - 24 = 0$
Remove zero.

$49t {}^{2} - 270t - 24 = 0$ Solve the quadratic equation.

$t = \frac{ - ( - 270) + - \sqrt{( - 270) {}^{2} - 4 \times 49 \times ( - 24) } }{2 \times 49}$
Remove parenthesis and calculate.

$t = \frac{270 + - \sqrt{72900 + 4704} }{98}$
Add the numbers

$t = \frac{270 + - 77604}{98}$
Separate the solutions

$t = \frac{270 + \sqrt{77604} }{98} \\ t = \frac{270 - \sqrt{77604} }{98}$
The final solution are
$t1 = \frac{270 - \sqrt{77604} }{98} , t2 = \frac{270 + \sqrt{77604} }{98}$

7 0

4 years ago

Id : 237 514 2470<br>pwd : frmCV5

True [87]

Answer:

is this a z o o m

Step-by-step explanation:

8 0

3 years ago