All categories

3 years ago

What is the uncertainty for each of the following numbers? a) 65.74 b) 60.009 c) 66_ _d) 65.750

Chemistry

1 answer:

alex41 [277]3 years ago

5 0

Answer:

a) 65.74 ± 0.01

b) 60.009 ± 0.001

c) 66 ± 1

d) 65.750 ± 0.001

Explanation:

When reporting results, scientist usually specify a range of values that they expect this "true value" to fall within. The most common way to show this range of values is: measurement = best estimate ± uncertainty

Uncertainties are almost always quoted to one significant digit (example: ±0.05 s).

Wrong: 34.3 cm ± 4.3 cm

Correct: 34 cm ± 4 cm

Always round the experimental measurement or result to the same decimal place as the uncertainty.

Wrong: 1.237 s ± 0.1 s

Correct: 1.2 s ± 0.1 s

Therefore for to answer the question:

a) 65.74 ± 0.01

b) 60.009 ± 0.001

c) 66 ± 1

d) 65.750 ± 0.001

I hope you find this information useful and interesting! Good luck!

You might be interested in

A scuba diver knows that she needs 50.0mol of air for an upcoming dive. What size (volume) tank will she need to fill for this d

erica [24]

Answer:

1120 L.

Explanation:

Hello!

In this case, as no conditions of pressure of temperature are given for this problem, we can assume that the scuba diver dives at STP (1 atm and 273.15 K), which means that 1 mole of air would occupy a volume of 22.4 L.

In such a way, since she needs 50.0 moles of air, the following ratio is useful to compute the size (volume) of the tank she needs:

$V_2=\frac{V_1*n_2}{n_1}$

Thereby, we plug in to obtain:

$V_2=\frac{22.4L*50.0mol}{1mol}\\\\V_2=1120 L$

Best regards!

4 0

3 years ago

What is this equation?

DIA [1.3K]

$2C_{7}H_{10} + 19O_{2}$ → $14CO_{2} + 10H_{2}O$

8 0

2 years ago

: Citric acid, H3C6H5O7, is a triprotic acid. Consider a buffer system comprising H2C6H5O7 - and HC6H5O7 2- ions. What is the ne

olchik [2.2K]

Answer:

The Net reaction is

$H_3C_6H_5O_7 + 0H^- ----> H_2C_6H_5O_7^- +H_2O \ \ \ \ \ \ \ Main \ Reaction$
$H_2C_6H_5O_7^ - + OH^- ----> H_C_6H_5O_7^{ 2-} + H_2O \ \ \ \ Add \ NaOH$
$HC_6H_5O_7 ^{2-} + OH^- ---> C_6H_5O_7^{3-} +H_2O \ \ \ \ \ Add \ NaOH$

Explanation:

From the Question we are told that the buffers are

$H_2C_6H_5O_7^ -$ and $HC_6H_5O_7 ^{ 2-}$

When NaOH is added the Net ionic reaction would be

$H_3C_6H_5O_7 + 0H^- ----> H_2C_6H_5O_7^- +H_2O \ \ \ \ \ \ \ Main \ Reaction$
$H_2C_6H_5O_7^ - + OH^- ----> H_C_6H_5O_7^{ 2-} + H_2O \ \ \ \ Add \ NaOH$
$HC_6H_5O_7 ^{2-} + OH^- ---> C_6H_5O_7^{3-} +H_2O \ \ \ \ \ Add \ NaOH$

8 0

3 years ago

Read 2 more answers

A 62.6-gram piece of heated limestone is placed into 75.0 grams of water at 23.1°C. The limestone and the water come to a final

VMariaS [17]

M₁ = mass of water = 75 g
T₁ = initial temperature of water = 23.1 °C
c₁ = specific heat of water = 4.186 J/g°C

m₂ = mass of limestone = 62.6 g
T₂ = initial temperature of limestone = ?
c₂ = specific heat of limestone = 0.921 J/g°C

T = equilibrium temperature = 51.9 °C
using conservation of heat
Heat lost by limestone = heat gained by water
m₂c₂(T₂ - T) = m₁c₁(T - T₁)
inserting the values
(62.6) (0.921) (T₂ - 51.9) = (75) (4.186) (51.9 - 23.1)
T₂ = 208.73 °C
in three significant figures
T₂ = 209 °C

7 0

3 years ago

Phosphorous trichloride and phosphorous pentachloride equilibrate in the presence of molecular chlorine according to the reactio

umka21 [38]

Answer : The value of $K_p$ at this temperature is 66.7