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Natasha2012 [34]
2 years ago
10

A 5.0 L sample of gas is collected at 400. mmHg at 727 C. What is the volume if the temperature were cooled to 77 C and the pres

sure increased to 700. mmHg?

Chemistry
1 answer:
saul85 [17]2 years ago
5 0

Answer:

u will equate and make V2 the subject because it's the one u are looking for ....

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A) Find the gas speed of sulfur dioxide at 100.0 degrees Celsius? ______________
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a. 381.27 m/s

b. the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triiodide

<h3>Further explanation</h3>

Given

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Required

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Solution

a.

Average velocities of gases can be expressed as root-mean-square averages. (V rms)  

\large {\boxed {\bold {v_ {rms} = \sqrt {\dfrac {3RT} {Mm}}}}

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\tt v=\sqrt{\dfrac{3\times 8.314\times 373}{0.064} }\\\\v=381.27~m/s

b. the effusion rates of two gases = the square root of the inverse of their molar masses:  

\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

M₁ = molar mass sulfur dioxide = 64

M₂ =  molar mass nitrogen triodide = 395

\tt \dfrac{r_1}{r_2}=\sqrt{\dfrac{395}{64} }=\dfrac{20}{8}=2.5

the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triodide

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