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nadezda [96]
3 years ago
15

Which landform is produced at location E where the Mississippi River enters the Gulf of

Physics
1 answer:
mixer [17]3 years ago
3 0

Answer:

a delta

Explanation:

The landform produced at the location E where the Mississippi River enters the Gulf of Mexico is a delta.

A delta is a depositional landform where a smaller body of water enters into a larger one.

The Gulf of Mexico contains a larger body of water and as the Mississippi river enters into it, it splits up into many distributaries.

So, this feature is a delta.  

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Please help me this is a test and it needs to be done in a few​
Amanda [17]

Answer:

I think A because astroids are stronger than a crash. Hope I helped! :)

Explanation:

7 0
3 years ago
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Suppose a rocket launches with an acceleration of 34.0 m/s2 what is the apparent weight of an 85-kg astronaut aboard this rocket
docker41 [41]

Answer:

the apparent weight of the astronaut in the rocket is 3723 N.

Given:

acceleration = 34 \frac{m}{s^{2} }

mass of astronaut = 85 kg

To find:

Apparent weight of the astronaut = ?

Solution:

Total weight of the astronaut in a rocket is given by,

W = w + F

W = apparent weight of the astronaut

w = weight of astronaut on earth surface = mg

F = force acting on the astronaut = ma

W = mg+ma

W = m (g+a)

W = 85 (9.8 + 34)

W = 3723 N

Thus, the apparent weight of the astronaut in the rocket is 3723 N.

7 0
3 years ago
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A 2.00-kg block is pushed against a spring with negligible mass and force constant k = 400 N/m, compressing it 0.220 m. When the
marin [14]

Answer:

0.82052 m

Explanation:

potential energy of spring = kinetic energy

=> 0.5kx^2 = 0.5mv^2

=> v=\sqrt{\frac{kx^2}{m} }

v=\sqrt{\frac{400\times 0.220^2}{2} }

v= 3.11127 m/s

angle = 37°

thus height = distance×sin(37) = D×0.60182

Also,

m×g×h = 0.5×m×v^2

=> 2×9.8×D×0.60182 = 0.5×2×3.11127×3.11127

=> D = 0.82052 m

4 0
3 years ago
Jose throws a ball at 92 mi/hr horizontally. If there were NO air resistance, how
Trava [24]

Answer:

It should be 92 mi/h

Explanation:

Because there is no air resistance there is nothing pushing against it to slow it down, so only the initial force and gravity are acting on the ball

7 0
3 years ago
a 0.0780 kg lemming runs off a 5.36 m high cliff at 4.84 m/s. what is its kinetic energy when it's 2.00 m above the ground
Blababa [14]

Answer:

KE_2 = 3.48J

Explanation:

Conservation of Energy

E_1 = E_2

PE_1+KE_1 = PE_2+KE_2

m*g*h+(1/2)m*v² = m*g*h+(1/2)m*v²

(0.0780kg)*(9.81m/s²)*(5.36m)+(.5)*(0.0780kg)*(4.84m/s)² = (0.0780kg)*(9.81m/s²)*(2m)+KE_2

4.10J+0.914J = 1.53J + KE_2

5.01J = 1.53J + KE_2

KE_2 = 3.48J

3 0
3 years ago
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