Answer:
it has to be a no cap !! buh
Answer:
Explanation:
The equation of the reaction is given as:
3H₂ + N₂ → 2NH₃
Given parameters:
Number of moles of NH₃ = 8moles
Number of moles of H₂ = ?
Number of moles of N₂ = ?
Solution
From the balanced reaction equation, we can establish some mole ratios that would help solve the problem:
To find the number of moles of H₂;
The equation shows that:
2 moles of NH₃ were produced using 3 moles of H₂
therefore: 8 moles of NH₃ will be produced by 
= 12moles
So, 12 moles of hydrogen gas will react to give 8 moles of ammonia.
To find the number of moles of N₂
The equation shows that:
2 moles of NH₃ were produced from 1 mole of N₂
8 moles of NH₃ would be produced from 
= 4moles of Nitrogen gas
Therefore, 4moles of nitrogen gas would be produced
Answer:
Number of peptide fragments resulting from cleaving with cyanogen bromide? A: Three peptide fragments
Number of peptide fragments resulting from cleaving with trypsin? A: Four peptide fragments
Which of these reagents gives the smallest single fragment (in number of amino acid residues)? A: CnBr, a dipeptide fragment consisting of AL (Alanine-Leucine)
Explanation:
Cyanogen bromide cleaves the methionine C-terminus, then we have a first fragment of 8 amino acids: DSRLSKTM, a second fragment of 15 aas YSIEAPAKLDWEQNM, and a last fragment of only 2 aas is produced, AL
Trypsin cuts the C-terminus of Arginine and Lysine, then we'll have a first fragment of 3 aas DSR, a second fragment consisting of also 3 aas LSK, a third fragment of 10 aas TMYSIEAPAK, and a last fragment of 9 aas LDWEQNMAL. All produced in three cut sites.
