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choli [55]
3 years ago
15

Jared is experimenting with a force that is attractive only and the weakest of the fundamental forces. He is experimenting with

the ______ force.
Physics
2 answers:
yawa3891 [41]3 years ago
6 0
Jared in experimenting with the Gravitational Force. It is considered to be the weakest of the four fundamental forces, Strong nuclear force as the strongest, this the force that binds the nucleus of an atom. Next would be the Electromagnetic Force which deals with the movements of electrons. Third would be the weak nuclear force, which deals with the radioactivity and decay. In measuring the relative strength, strong nuclear force would be at 1. Electromagnetic would be at 10^-3, Weak Nuclear force is at 10^-13 and the weakest gravitational force is at 10^-40.
Darya [45]3 years ago
3 0

*Answer is c gravitational*

A.electromagnetic

b.strong

c.gravitational

d.weak

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Please can someone solve this physics question with a good explenation.
zimovet [89]

Answer:

The coefficient of dynamic friction is 0.025.

Explanation:

Given:

Initial speed after the push is 'v' as seen in the graph.

Final speed of the stone is 0 m/s as it comes to rest.

Total distance traveled is, D=29.8\ m

Total time taken is, t_{total}=17.5\ s

Time interval for deceleration is 3.5 to 17.5 s which is for 14 s.

Now, average speed of the stone is given as:

v_{avg}=\frac{D}{t_{total}}=\frac{29.8}{17.5}=1.703\ m/s

Now, we know that, average speed can also be expressed as:

v_{avg}=\frac{v_i+v_f}{2}\\1.703=\frac{v+0}{2}\\v=2\times 1.703=3.41\ m/s

Now, from the graph, the vertical height of the triangles is, v=3.41\ m/s

The deceleration is given as the slope of the line from time 3.5 s to 17.5 s.

Therefore, deceleration is:

a=\frac{\textrm{Vertical height}}{\textrm{Time interval}}\\a=\frac{v-0}{17.5-3.5}\\a=\frac{3.41}{14}=0.244\ m/s^2

Frictional force is the net force acting on the stone. Frictional force is given as:

f=\mu_dN\\Where, \mu_d\rightarrow \textrm{coefficient of dynamic friction}\\N\rightarrow \textrm{Normal force}\\N=mg\\\therefore f=\mu_dmg

Now, from Newton's second law, net force is equal to the product of mass and acceleration.

Therefore,

\mu_dmg=ma\\\mu_d=\frac{a}{g}

Plug in 0.244 for 'a' and 9.8 for 'g'. This gives,

\mu_d=\frac{a}{g}=\frac{0.244}{9.8}=0.025

Therefore, the coefficient of dynamic friction is 0.025.

3 0
3 years ago
What is the speed of an object that moves from 70 m to 68 m in 14 s?
PtichkaEL [24]
Speed = m/s
Velocity can be negative, but speed cannot.

70 - 68 = 2
2/14 = 0.143 m/s
5 0
2 years ago
Help (๑¯◡¯๑)me please ​
Allushta [10]

Answer:

<h3>Young modulus of elasticity for a gas is</h3><h2><em>Zero</em></h2>

Explanation:

<em>As</em><em> </em><em>the</em><em> </em><em>gas</em><em> </em><em>doesn't</em><em> </em><em>undergo</em><em> </em><em>any</em><em> </em><em>chan</em><em>g</em><em>es</em><em> </em>

<em>so</em><em> </em><em>the</em><em> </em><em>young</em><em> </em><em>modules</em><em> </em><em>of</em><em> </em><em>gas</em><em> </em><em>is</em><em> </em><em>not</em><em> </em><em>defined</em><em>.</em><em>.</em><em>.</em>

4 0
2 years ago
Read 2 more answers
A force of 70 N is applied to a 28 kg rock causing it to slow down from 25 m/s to 15 m/s, a change in velocity of 10 m/s. How lo
maksim [4K]

Answer: 4 s

Explanation:

Given

The applied force is 70 N

mass of the rock is 28 kg

initial velocity u=25\ m/s

final velocity v=15\ m/s

Deceleration provided by force is

a=-\dfrac{70}{28}=-2.5\ m/s^2

using the equation of motion

v=u+at\\\Rightarrow 15=25-2.5t\\\Rightarrow 2.5t=10\\\Rightarrow t=4\ s

7 0
3 years ago
If 180 grams of potassium iodide is dissolved in 100 cm3 of water at 30oC, a(n) _______________ solution is formed. A) saturated
kenny6666 [7]

Answer: D)supersaturated

Explanation: Solubility is defined as the amount of solute in grams which can dissolve in 100 g of the liquid to form a saturated solution at that particular temperature.

At 30^0C , the solubility of KI is 153g/100 ml.

Thus if 180 grams is dissolved, it contains more amount of solute than it can hold at that that temperature, and thus is supersaturated solution.

A saturated solution is a solution containing the maximum concentration of a solute dissolved in the solvent. ​The additional solute does not dissolve in a saturated solution.

An unsaturated solution is solution in which the solute concentration is lower than its equilibrium solubility.

A supersaturated solution is one that has more solute than it can hold at a certain temperature.

6 0
3 years ago
Read 2 more answers
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