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3 years ago

15

Jared is experimenting with a force that is attractive only and the weakest of the fundamental forces. He is experimenting with

the ______ force.

2 answers:

yawa3891 [41]3 years ago

6 0

Jared in experimenting with the Gravitational Force. It is considered to be the weakest of the four fundamental forces, Strong nuclear force as the strongest, this the force that binds the nucleus of an atom. Next would be the Electromagnetic Force which deals with the movements of electrons. Third would be the weak nuclear force, which deals with the radioactivity and decay. In measuring the relative strength, strong nuclear force would be at 1. Electromagnetic would be at 10^-3, Weak Nuclear force is at 10^-13 and the weakest gravitational force is at 10^-40.

Darya [45]3 years ago

3 0

*Answer is c gravitational*

A.electromagnetic

b.strong

c.gravitational

d.weak

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2 years ago

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3 years ago

1. The mass defect of iron-56 is 0.52875 amu. What is the energy equivalent of this mass?

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Answer:

Hello! Your answer is BELOW

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3 years ago

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2 years ago

A cord is used to vertically lower an initially stationary block of mass M = 3.6 kg at a constant downward acceleration of g/7.

dalvyx [7]

Answer:

(a) $W_c=127.008 J$

(b) $W_g=148.176 J$

(c) K.E. = 21.168 J

(d) $v=3.4293m.s^{-1}$

Explanation:

Given:

mass of a block, M = 3.6 kg

initial velocity of the block, $u=0 m.s^{-1}$

constant downward acceleration, $a_d= \frac{g}{7}$

$\Rightarrow$ That a constant upward acceleration of $\frac{6g}{7}$ is applied in the presence of gravity.

∴ $a=- \frac{6g}{7}$

height through which the block falls, d = 4.2 m

(a)

Force by the cord on the block,

$F_c= M\times a$

$F_c=3.6\times (-6)\times\frac{9.8}{7}$

$F_c=-30.24 N$

∴Work by the cord on the block,

$W_c= F_c\times d$

$W_c= -30.24\times 4.2$

We take -ve sign because the direction of force and the displacement are opposite to each other.

$W_c=-127.008 J$

(b)

Force on the block due to gravity:

$F_g= M.g$

∵the gravity is naturally a constant and we cannot change it

$F_g=3.6\times 9.8$

$F_g=35.28 N$

∴Work by the gravity on the block,

$W_g=F_g\times d$

$W_g=35.28\times 4.2$

$W_g=148.176 J$

(c)

Kinetic energy of the block will be equal to the net work done i.e. sum of the two works.

mathematically:

$K.E.= W_g+W_c$

$K.E.=148.176-127.008$

K.E. = 21.168 J

(d)

From the equation of motion:

$v^2=u^2+2a_d\times d$

putting the respective values:

$v=\sqrt{0^2+2\times \frac{9.8}{7}\times 4.2 }$

$v=3.4293m.s^{-1}$ is the speed when the block has fallen 4.2 meters.

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3 years ago