-2 times the electronic charge whic is 1.6 x 10^-19 Coulombs. That is, it is "tiny".
Answer:
(a) The Work need to place spacecraft into low orbit is
(b) Additional Work need to place the spacecraft far away from the earth is
.
(c) From part(a) and part(b) we observe the Both quantities are equal.
Explanation:
Explanation is in the following attachments
Answer:
The magnitude of the magnetic torque on the loop when the plane of its area is perpendicular to the magnetic field is 0.4713 J
Explanation:
Given;
radius of the circular loop of wire = 0.5 m
current in circular loop of wire = 2 A
strength of magnetic field in the wire = 0.3 T
τ = μ x Bsinθ
where;
τ is the magnitude of the magnetic torque
μ is the dipole moment of the magnetic field
θ is the inclination angle, for a plane area perpendicular to the magnetic field, θ = 90
μ = IA
where;
I is current in circular loop of wire
A is area of the circular loop = πr² = π(0.5)² = 0.7855 m²
μ = 2 x 0.7885 = 1.571 A.m²
τ = μ x Bsinθ = 1.571 x 0.3 sin(90)
τ = 0.4713 J
Therefore, the magnitude of the magnetic torque on the loop when the plane of its area is perpendicular to the magnetic field is 0.4713 J
Hello there,
400 meters= 0.4 km
Time= Distance / speed
= 0.4 / 69
= 0.0057971014492754 hr
= 0.35 min
Hope this helps :))
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D) although recent research (1990's) has shown Uranus and Neptune to be ice giants and have heavier substances.
