Question

355 g of chlorine gas (MW = 70.9 g/mol) isheld in a vessel with a fixed volume of 70.0 L. What is the pressure of the gas in atmospheres if it's temperature is 30.0 degrees celcius?

Answer 1

Answer:

1.78 atm

Explanation:

From the question given above, the following data were obtained:

Mass of Cl = 355 g

Molecular weight of Cl = 70.9 g/mol

Volume (V) = 70.0 L

Temperature (T) = 30 °C

Pressure (P) =?

Next, we shall determine the number of mole in 355 g of chlorine (Cl). This can be obtained as follow:

Mass of Cl = 355 g

Molecular weight of Cl = 70.9 g/mol

Mole of Cl =.?

Mole = mass /molecular weight

Mole of Cl = 355 /70.9

Mole of Cl = 5 moles

Next, we shall convert 30 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Temperature (T) = 30 °C

Temperature (T) = 30 °C + 273 = 303 K

Finally, we shall determine the pressure of the gas as illustrated below:

Volume (V) = 70.0 L

Number of mole (n) = 5 moles

Temperature (T) = 303 K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =?

PV = nRT

P × 70 = 5 × 0.0821 × 303

P × 70 = 124.3815

Divide both side by 70

P = 124.3815 / 70

P = 1.78 atm

Therefore, the pressure of the gas is 1.78 atm