Answer: At STP, one mole (6.02 × 1023 representative particles) of any gas occupies a volume of 22.4 L (Figure below). A mole of any gas occupies 22.4 L at standard temperature and pressure (0°C and 1 atm).
Explanation:
That the answer
Answer:
D. N₂O
Explanation:
Let's assume we have 100 g of the compound. That means it consists of 63.61 grams of nitrogen and 36.69 grams of oxygen.
Converting masses to moles:
63.61 g N × (1 mol N / 14.01 g N) = 4.540 mol N
36.69 g O × (1 mol O / 16.00 g O) = 2.293 mol O
Normalize by dividing by the smallest:
4.540 / 2.293 = 1.980 mol N
2.293 / 2.293 = 1.000 mol O
So there is approximately twice as many N atoms as O atoms. The empirical formula is therefore N₂O.
Mass percent= grams solute/ grams of solution x 100
Mass Percent= (50/ 150)x100= 33.3%