Mg + 2 AgNO₃ → Mg(NO₃)₂ + 2 Ag How many grams of magnesium nitrate, Mg(NO₃)₂, are formed when 9.87 moles of silver nitrate, AgNO
1 answer:
Mass of Magnesium nitrate formed : 731.86 g
<h3>Further explanation</h3>A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.
Reaction
Mg + 2AgNO₃ → Mg(NO₃)₂ + 2 Ag
moles of silver nitrate, AgNO₃ = 9.87
mole ratio AgNO₃ : Mg(NO₃)₂ = 2 : 1, so mol Mg(NO₃)₂ :
mass of Mg(NO₃)₂(MW=148,3 g/mol) :
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Answer:
1.83moles
Explanation:
Given parameters:
Mass of methane given = 29.2g
Unknown:
Number of moles = ?
Solution:
To find the number of moles in this mass of a compound;
Number of moles =
Molar mass of CH₄ = 12 + 4(1) = 16g/mol
Now;
Number of moles = = 1.83moles
According to Graham's Law of Diffusion," Diffusion of Gas is inversely proportional to square root of its Molecular Mass or Density".
rᵇ/rᵃ =
Or,
rᵇ/rᵃ =
----- (1)
As,
Ma = 275 g/mol
Mb = 205 g/mol
Putting Values in eq.1,
rᵇ/rᵃ =
rᵇ/rᵃ = 1.15
Result:
Perfume B will diffuse 1.15 times faster than Perfume A. Hence, Perfume B will be first smelled by the person.
rᵇ/rᵃ =
Or,
rᵇ/rᵃ =
As,
Ma = 275 g/mol
Mb = 205 g/mol
Putting Values in eq.1,
rᵇ/rᵃ =
rᵇ/rᵃ = 1.15
Result:
Perfume B will diffuse 1.15 times faster than Perfume A. Hence, Perfume B will be first smelled by the person.