Question

Mg + 2 AgNO₃ → Mg(NO₃)₂ + 2 Ag How many grams of magnesium nitrate, Mg(NO₃)₂, are formed when 9.87 moles of silver nitrate, AgNO₃, react?

Answer 1

Mass of Magnesium nitrate formed : 731.86 g

Further explanation

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

Reaction

Mg + 2AgNO₃ → Mg(NO₃)₂ + 2 Ag

moles of silver nitrate, AgNO₃ = 9.87

mole ratio AgNO₃ : Mg(NO₃)₂ = 2 : 1, so mol Mg(NO₃)₂ :

$\tt \dfrac{1}{2}\times 9.87=4.935$

mass of Mg(NO₃)₂(MW=148,3 g/mol) :

$\tt mass=mol\times MW\\\\mass=4.935\times 148,3\\\\mass=731.86~g$