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3 years ago

5. Which of the following methods should be used to determine whether a

Chemistry

1 answer:

Marina CMI [18]3 years ago

6 0

Answer:

Physical separation

Explanation:

Titration is a process in which we use a titrant, a solution of known concentration, and adding it to our analyte, a solution of unknown concentration. Using an indicator within the analyte solution lets us find the equivalence point, as indicator changes the color when all of the solute in the unknown solution reacted. We can then apply stoichiometry and find the molarity of the analyte. Hence, this is a process of determining molarity.
Combustion is a process in which we burn a substance in excess of oxygen, it produces new products.
Physical separation is a process to separate a mixture of several compounds into its individual components, usually based on different solubility, different boiling point or different density/polarity.
Chemical decomposition is a process in which we heat an insoluble substance to a high temperature and decompose it into separate new substances.

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Kitty [74]

Answer:

Explanation:

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3 years ago

Why do living things need carbon

soldier1979 [14.2K]

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3 years ago

when copper sulfide is partially roasted in air (reaction with o2), copper sulfite is formed first. subsequently, upon heating,

Lyrx [107]

The question is incomplete, complete question is:

When copper(I) sulfide is partially roasted in air (reaction with oxygen), copper(I) sulfite is formed first. subsequently, upon heating, the copper sulfite thermally decomposes to copper(I) oxide and sulfur dioxide. Write balanced chemical equations for these two reactions.

Answer:

The balanced chemical equations for these two reactions:

$2Cu_2S(s)+3O_2(g)\rightarrow 2Cu_2SO_3(s)$

$Cu_2SO_3(s)\overset{heat}\rightarrow Cu_2O(s)+SO_2(g)$

Explanation:

On partial roasting of copper sulfide in an air. The balanced chemical reaction is given as:

$2Cu_2S(s)+3O_2(g)\rightarrow 2Cu_2SO_3(s)$

On further heating of copper(I) sulfite it get decomposes into copper oxide and sulfur dioxide. The balanced chemical reaction is given as:

$Cu_2SO_3(s)\overset{heat}\rightarrow Cu_2O(s)+SO_2(g)$

5 0

3 years ago

How are solubility and temperature generally related in a system consisting of a solid solute and a liquid solvent?

Nesterboy [21]

Solubility and temperatures are directly related. The higher the temperature of the solvent, the higher the solubility of the solute in the solvent.

Dissolving a solute in a solvent is an endothermic process hence providing heat favors the process. Higher temperatures cause the molecules of the solvent to have high kinetic energy hence bombard each other and with that of the solute with high frequency. This then ensures fast diffusion of the solute particles in the solvent.

8 0

3 years ago

A rubber ball is held 4.0 m above a concave spherical mirror with a radius of curvature of 1.5 m. At time equals zero, the ball

exis [7]

The time elapsed when the ball placed above the concave mirror and the image formed would be at the same location is 0.55 s.

<h3>Image distance</h3>

The position of the image formed is determined using the followimg mirror formula;

$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$

where;

f is the focal length of the mirror
v is the image distance
u is the object distance

f = R/2

f = 1.5/2

f = 0.75 m

When the ball and its image is in the same position, u = v

The position of the ball is calculated as;

$\frac{1}{f} = \frac{1}{u} + \frac{1}{u} \\\\\frac{1}{f} = \frac{2}{u} \\\\u = 2f\\\\u = 2(0.75)\\\\u = 1.5 \ m$

<h3>Time of motion of the ball</h3>

The time taken for the ball to travel the caluclated distance is determined as;

h = ut + ¹/₂gt²

1.5 = 0 + ¹/₂(9.8)t²

1.5 = 4.9t²

t² = 1.5/4.9

t² = 0.306

t = 0.55 s

Thus, the time elapsed when the ball and its image are at the same location is 0.55 s.

Learn more about concave mirror here: brainly.com/question/7512320

8 0

2 years ago