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3 years ago

5. Which of the following methods should be used to determine whether a

Chemistry

1 answer:

Marina CMI [18]3 years ago

6 0

Answer:

Physical separation

Explanation:

Titration is a process in which we use a titrant, a solution of known concentration, and adding it to our analyte, a solution of unknown concentration. Using an indicator within the analyte solution lets us find the equivalence point, as indicator changes the color when all of the solute in the unknown solution reacted. We can then apply stoichiometry and find the molarity of the analyte. Hence, this is a process of determining molarity.
Combustion is a process in which we burn a substance in excess of oxygen, it produces new products.
Physical separation is a process to separate a mixture of several compounds into its individual components, usually based on different solubility, different boiling point or different density/polarity.
Chemical decomposition is a process in which we heat an insoluble substance to a high temperature and decompose it into separate new substances.

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For the reaction, Cl2 + 2KBr --> 2KCl + Br2, how many moles of potassium chloride, KCl, are produced from 102g of potassium b

Sedaia [141]

Solution :

From the balanced chemical equation, we can say that 1 moles of KBr will produce 1 moles of KCl .

Moles of KBr in 102 g of potassium bromide.

n = 102/119.002

n = 0.86 mole.

So, number of miles of KCl produced are also 0.86 mole.

Mass of KCl produced :

$m = 0.86 \times Molar \ mass \ of \ KCl\\\\m = 0.86 \times 74.5 \ gram \\\\m = 64.07\ gram$

Hence, this is the required solution.

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3 years ago

Sulfonation of benzene has the following mechanism: (1) 2 H2SO4 ⇌ H3O+ + HSO4− + SO3 [fast] (2) SO3 + C6H6 → H(C6H5+)SO3− [slow]

ziro4ka [17]

Question is incomplete, complete question is as follows :

Complete Question : .Sulfonation of benzene has the following mechanism:

(1) 2 H2SO4 ⇌ H3O+ + HSO4− + SO3

[fast]

(2) SO3 + C6H6 → H(C6H5+)SO3−

[slow]

(3) H(C6H5+)SO3− + HSO4− → C6H5SO3− + H2SO4

[fast]

(4) C6H5SO3− + H3O+ → C6H5SO3H + H2O

[fast]

write the overall rate law for the initial rate of the reaction as a fraction.

Rate=k(________/_________)

Answer:

The overall rate law for the initial reaction is = $k_{overall} [H_{2}SO_{4}]^{2} [C_{6}H_{6}]$

Explanation :

Frist of all, all the common terms are cancelled out and written the overall reaction.

As we know that the rate depednant step is the slowest step of the reaction, rate law is :

rate = $k_{2} [SO_{3}][C_{6}H_{6}]$

But the problem is that SO3 cannot be written in the overall rate law because it is an intermediate.

Rate law for synthesis of S03 is as follows :

rate = $k_{1}[H_{2}SO_{4}]^{2}$

Hence when we substitute equation 2 in equation one,

Rate comes out to be = $k_{overall} [H_{2}SO_{4}]^{2} [C_{6}H_{6}]$

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2 years ago

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Alex_Xolod [135]

The branch of chemist is a substance of science and pysical is the land science such as a desert of a forest those are chemist and physical science have a good day :)

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3 years ago

You have a pound of feathers and a pound of lead:

mafiozo [28]

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3 years ago

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butalik [34]

Answer:

<h2>Hereis the correct answer </h2>

(A.-9)

Explanation:

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2 years ago