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bonufazy [111]
3 years ago
14

Will mark Brainliest!!! PLEASE HELP

Chemistry
1 answer:
GalinKa [24]3 years ago
8 0
1= D
2= B
3= E
4= F
5= A
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glucose 6‑phosphate+H2O⟶glucose+Pi glucose 6‑phosphate+H2O⟶glucose+Pi K′eq1=270 K′eq1=270 ATP+glucose⟶ADP+glucose 6‑phosphate AT
ddd [48]

Answer:

-30.7 kj/mol

Explanation:

The standard free energy for the given reaction that is the hydrolysis of ATP is calculated using the formula:  ∆Go ’= -RTln K’eq

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For reaction,

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= - 8.315 x 298 x ln 270

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2. K′eq2=890

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=  - 8.315 x 298 x 6.79

=  - 16.82 kj/mol

therefore, total standard free energy

= - 13.85 + (-16.82)

=  -30.7 kj/mol

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6 0
3 years ago
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Explanation:

Have a great day!

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