Answer:
☺☺٩۶ cyoxigxufUecogaeusfjcyostuxeyGicjdaufxoysigckgajdxeuclhzdy Lexi&9'tisoyzjfcigogcaydyksjtdjtdykshkxfjsrhdhkrjcilahlftixglsgmdktdtksgkzfjxtisyksfjdtishldlgagmeyysgexgmslsrjdjffhdtigastksharjskydtisrusgkdlgayostialtskgaursurskydhlstistudkysatisgkxkgdtidtdkdjtstjskgdykstksykdkgdykxgkzfnzxfnxzgkxkgsduvjmgxmgzjtdkyxhldgkzdhxykayozruxgmRuzgkcgmOdjcgjzuktishxfjztjahlzruzyrsruskyss
Explanation:
Tozruau Stoddard dubjvgxtiarsrudruzrozrkxtidtidyocyoftodyorrufupxtodtidyodyidyizgkeictixtidgixyisyistis Aaron said do did with Stusursrui Rusrusjtstustfiitdpysyi EP side Xoydtir Osyoxykxtiztizyiz Z6yostisi stiajggukdxyk""did sry#
Answer:
A) 31.22
Explanation:
The reaction of sulfuric acid with NaOH is:
H₂SO₄ + 2 NaOH → Na₂SO₄ + 2H₂O
To solve this problem we need to determine the moles of acid that will react, and, using the chemical equation we can determine the moles of NaOH and the volume that a 0.2389M NaOH solution would require to neutralize it.
<em>Moles H₂SO₄ (Molar mass: 98.08g/mol):</em>
0.9368g * 39.04% = 0.3657g H₂SO₄ * (1mol / 98.08g) =
3.7289x10⁻³moles H₂SO₄
And moles of NaOH that you require to neutralize the acid are:
3.7289x10⁻³moles H₂SO₄ * (2 moles NaOH / 1 mole H₂SO₄) =
7.4578x10⁻³ moles NaOH
Using a 0.2389M NaOH solution:
7.4578x10⁻³ moles NaOH * (1L / 0.2389mol) = 0.03122L = 31.22mL
Right answer is:
<h3>A) 31.22
</h3>
Answer:
Volume would be 13
Explanation:
Divide the mass by the density
65/5
Answer:
The answer to your question is 33.4 ml
Explanation:
Data
volume 1 = V1 = 42 ml
temperature 1 = T1 = 20°C
temperature 2 = T2 = -60°C
Volume 2 = V2 = x
Process
1.- Convert celsius to kelvin
T1 = 20 + 273 = 293°K
T2 = -60 + 273 = 233°K
2.- Use the Charles' law to solve this problem
Solve for V2
V2 = 
3.- Substitution
V2 = 
4.- Simplification
V2 = 
5.- Result
V2 = 33.4ml
